D\u01b0\u1edbi \u0111\u00e2y ch\u00fang t\u00f4i t\u1ed5ng h\u1ee3p m\u1ed9t s\u1ed1 c\u00e2u h\u1ecfi tr\u1eafc nghi\u1ec7m b\u00e0i t\u1eadp \u0111\u1ea1o h\u00e0m \u0111\u1ec3 c\u00e1c h\u1ecdc sinh c\u00f3 th\u1ec3 tham kh\u1ea3o v\u00e0 r\u00e8n luy\u1ec7n th\u00eam c\u00e1c k\u1ef9 n\u0103ng v\u1ec1 gi\u1ea3i to\u00e1n tr\u1eafc nghi\u1ec7m \u0111\u01b0\u1ee3c t\u1ef1 tin v\u00e0 v\u1eefng v\u00e0ng h\u01a1n.<\/p>\n

C\u00e2u 1 :<\/u><\/strong> Cho bi\u1ebft s\u1ed1 gia \u0394y c\u1ee7a h\u00e0m s\u1ed1 y = x^{2<\/sup> + 2 t\u1ea1i xo = -1 l\u00e0:<\/p>\n}

\n
1. (\u0394x )2<\/sup> + 2\u0394x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. (\u0394x )2<\/sup> – 2\u0394x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. (\u0394x )2<\/sup> + 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.(\u0394x )2<\/sup> –\u00a0 2<\/li>\n<\/ol>\n

   C\u00e2u 2: <\/u><\/strong>\u00a0Khi x\u00e9t 1 h\u00e0m s\u1ed1 y = f(x) = |x| c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i 1 \u0111i\u1ec3m x_{0<\/sub> = 0 hay kh\u00f4ng, 1 h\u1ecdc sinh l\u00e0m c\u00e1c b\u01b0\u1edbc sau:<\/p>\n}

   (I)\u00a0 T\u00ednh \u0394y = f(0+\u0394x) \u2013 f(0) = |\u0394x| \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0(II) L\u1eadp t\u1ec9 s\u1ed1 Dy\/Dx = |\u0394x|\u0394x<\/p>\n

   (III) T\u00ednh \u00a0\u00a0= 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 (IV)\u00a0 K\u1ebft lu\u1eadn f \u2019(0) = 1\u00a0 .<\/p>\n

   Trong c\u00e1c l\u1eadp lu\u1eadn tr\u00ean sai t\u1eeb b\u01b0\u1edbc n\u00e0o ?<\/p>\n

   \n
   1. (I) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. (II) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. (III) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. (IV)<\/li>\n<\/ol>\n

      C\u00e2u 3:<\/u><\/strong>\u00a0 <\/strong>T\u00ednh \u0111\u1ea1o h\u00e0m c\u1ee7a 1 h\u00e0m s\u1ed1 \u00a0\u00a0l\u00e0:<\/p>\n

      \n
      1. 2x + 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0D. \u00a0\u00a0\u00a0\u00a0<\/li>\n<\/ol>\n

         C\u00e2u 4:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 \u00a0 . Khi \u0111\u00f3 ta c\u00f3:<\/p>\n

         \n
         1. f\u2019(0) = -1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. f\u2019(1) = -3\/4 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. f(0) = 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. f(1) = 1\/3<\/li>\n<\/ol>\n

            C\u00e2u 5:<\/u><\/strong> T\u00ednh \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = ln(sinx):<\/p>\n

            \n
            1. tgx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. cotgx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 1\/sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 1\/cosx<\/li>\n<\/ol>\n

               C\u00e2u 6:<\/u><\/strong>\u00a0 <\/strong>T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = 2^{x<\/sup>.3x<\/sup>:<\/p>\n}

               \n
               1. 6xln<\/sup>6 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 6x<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 2x<\/sup> + 3x<\/sup>. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 2x-1<\/sup>.3x-1<\/sup><\/li>\n<\/ol>\n

                  C\u00e2u 7:<\/u><\/strong>\u00a0 <\/strong>T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = tg3x l\u00e0:<\/p>\n

                  \n
                  1. \u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. \u00a0 \u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.<\/li>\n<\/ol>\n

                     C\u00e2u 8:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 y= (x-1)(x+2)(2x -3)\u00a0 . T\u00ednh f\u2019(-2) b\u1eb1ng\u00a0 :<\/p>\n

                     \n
                     1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 21 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. -21 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 31<\/li>\n<\/ol>\n

                        C\u00e2u 9:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 \u00a0<\/p>\n

                        T\u00ecm t\u1eadp nghi\u1ec7m c\u1ee7a b\u1ea5t ph\u01b0\u01a1ng tr\u00ecnh\u00a0 f\u2019(x) \u2264 0:<\/p>\n

                        \n
                        1. \u03a6 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.(0;+\u221e) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.[-2;2] \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. (-\u221e; +\u221e)<\/li>\n<\/ol>\n

                           C\u00e2u 10: <\/u><\/strong>\u00a0<\/strong>T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = 1 –<\/strong> cotg^{2<\/sup>x l\u00e0:<\/p>\n}

                           \n
                           1. -2cotgx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. –<\/strong>2cotgx(1+cotg2<\/sup>x) \u00a0 \u00a0 \u00a0 \u00a0C. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 2cotgx(1+cotg2<\/sup>x)<\/li>\n<\/ol>\n

                              C\u00e2u 11:\u00a0 <\/u><\/strong>Cho 1 h\u00e0m s\u1ed1 f(x) = ln(4x \u2013 x^{2<\/sup>) . T\u00ecm f\u2019(2) b\u1eb1ng :<\/p>\n}

                              \n
                              1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. \u0110\u00e1p s\u1ed1 kh\u00e1c<\/li>\n<\/ol>\n

                                 C\u00e2u 12 :<\/u><\/strong>\u00a0 Cho 1 h\u00e0m s\u1ed1 \u00a0. T\u00ecm \u0192”(-\u03a0\/2):<\/p>\n

                                 \n
                                 1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.-2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 5<\/li>\n<\/ol>\n

                                    C\u00e2u 13:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ea5p 2007 c\u1ee7a 1 h\u00e0m s\u1ed1 y = cosx:<\/p>\n

                                    \n
                                    1. 2007sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. -2007sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.-sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. sinx<\/li>\n<\/ol>\n

                                       C\u00e2u 14:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ea5p 2008 c\u1ee7a 1 h\u00e0m s\u1ed1 y = e^{-x<\/sup>:<\/p>\n}

                                       \n
                                       1. 2008e-x<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. -2008 e-x<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C .e-x<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. -e-x<\/sup><\/li>\n<\/ol>\n

                                          C\u00e2u 15<\/u><\/strong>: Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ngTa c\u00f3:<\/p>\n

                                          \n
                                          1. y\u201d = y \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. y\u201d = -y \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.y\u201d = 2y \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. y\u201d = -2y<\/li>\n<\/ol>\n

                                             C\u00e2u 16:<\/u><\/strong> Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng\u00a0 y = 2ex.sinx<\/p>\n

                                             T\u00ecm gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c A = y\u201d-2y\u2019+2y \u2013 2:<\/p>\n

                                             \n
                                             1. -2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. \u0110\u00e1p s\u1ed1 kh\u00e1c<\/li>\n<\/ol>\n

                                                C\u00e2u 17:<\/u><\/strong> T\u00ecm h\u1ec7 s\u1ed1 g\u00f3c c\u1ee7a ti\u1ebfp tuy\u1ebfn c\u1ee7a 1 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u00a0\u00a0t\u1ea1i giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00f3 v\u1edbi tr\u1ee5c tung:<\/p>\n

                                                \n
                                                1. -2\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. -1<\/li>\n<\/ol>\n

                                                   C\u00e2u 18:<\/u><\/strong> Ti\u1ebfp tuy\u1ebfn c\u1ee7a 1 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u00a0t\u1ea1i 1 \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 x_{0<\/sub> = – 1 th\u00ec c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0:<\/p>\n}

                                                   \n
                                                   1. y = -x – 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.y= -x + 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. y= x -1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. y = x + 2<\/li>\n<\/ol>\n

                                                      C\u00e2u 19 :<\/u><\/strong> Ho\u00e0nh \u0111\u1ed9 c\u1ee7a 1 ti\u1ebfp \u0111i\u1ec3m c\u1ee7a ti\u1ebfp tuy\u1ebfn song song v\u1edbi tr\u1ee5c ho\u00e0nh c\u1ee7a 1 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u00a0 l\u00e0:<\/p>\n

                                                      \n
                                                      1. -1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. \u0110\u00e1p s\u1ed1 kh\u00e1c<\/li>\n<\/ol>\n

                                                         C\u00e2u 20: <\/u><\/strong>Ti\u1ebfp tuy\u1ebfn c\u1ee7a 1 \u0111\u1ed3 thi h\u00e0m s\u1ed1 \u00a0t\u1ea1i 1 giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u0111\u00f3 v\u1edbi tr\u1ee5c tung c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh l\u00e0:<\/p>\n

                                                         \n
                                                         1. y = x – 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.y= x + 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. y= x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. y = -x<\/li>\n<\/ol>\n

                                                            <\/u>C\u00e2u 21:<\/u><\/strong> \u00a0Cho 1 h\u00e0m s\u1ed1 : \u00a0\u00a0. Th\u00ec ph\u01b0\u01a1ng tr\u00ecnh y\u2019 = 0 c\u00f3 2 nghi\u1ec7m x_{1<\/sub> , x2<\/sub> .V\u1eady x1<\/sub> . x2<\/sub> =<\/p>\n}

                                                            \n
                                                            1. 5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 8 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. -5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. -8<\/li>\n<\/ol>\n

                                                               C\u00e2u 22 :<\/u><\/strong> \u00a0\u00a0Cho 1 h\u00e0m s\u1ed1 : \u00a0. Khi \u0111\u00f3 ta c\u00f3 :<\/p>\n

                                                               \n
                                                               1. – 5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 7 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D .-7<\/li>\n<\/ol>\n

                                                                  C\u00e2u 23 :<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 : \u00a0. T\u00ednh :<\/p>\n

                                                                  \n
                                                                  1. – 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. -7<\/li>\n<\/ol>\n

                                                                     C\u00e2u 24 :<\/u><\/strong> \u00a0\u00a0Cho 1 h\u00e0m s\u1ed1 : \u00a0\u00a0\u00a0. T\u00ednh : <\/p>\n

                                                                     \n
                                                                     1. cosx – sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. sinx – cosx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. sinx + cosx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. cosx<\/li>\n<\/ol>\n

                                                                        C\u00e2u 25 :<\/u><\/strong> \u00a0\u00a0Cho 1 h\u00e0m s\u1ed1 : \u00a0. T\u00ecm nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh : y’- y = e\u00b2 , x =<\/p>\n

                                                                        \n
                                                                        1. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. -2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 1 \/ 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.-1 \/ 2<\/li>\n<\/ol>\n

                                                                           C\u00e2u 26:<\/u><\/strong> \u00a0\u00a0Cho 1 h\u00e0m s\u1ed1 : . T\u00ednh: \u00a0y’cosx – y” =<\/p>\n

                                                                           \n
                                                                           1. y.sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. y.cosx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. – y.sinx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 – y.cosx<\/li>\n<\/ol>\n

                                                                              C\u00e2u 27:<\/u><\/strong> \u00a0\u00a0Cho 1 h\u00e0m s\u1ed1 y = x^{3<\/sup>+1 . T\u00ednh gi\u00e1 tr\u1ecb\u00a0 \u00a0\u00a0t\u1ea1i\u00a0 x_{0<\/sub> = -1 l\u00e0 :<\/p>\n}}

                                                                              A. (\u0394x)^{2<\/sup>-3\u0394x+3. \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. (\u0394x)2<\/sup>+3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. \u0394x+3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 3\u0394x +3.<\/p>\n}

                                                                              C\u00e2u 28:<\/u><\/strong> \u00a0\u00a0T\u00ednh \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y=1\/3x\u00b3-4x\u00b2+3x-2 t\u1ea1i \u0111i\u1ec3m \u00a0x_{0 <\/sub>= 2 l\u00e0:<\/p>\n}

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                                                                              1. 23 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.27 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 15 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.-9<\/li>\n<\/ol>\n

                                                                                 C\u00e2u 29:<\/u><\/strong> \u00a0\u00a0Cho h\u00e0m s\u1ed1 y = excosx. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c A = y^{(3) <\/sup>+ 4y l\u00e0 :<\/p>\n}

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                                                                                 1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. -2<\/li>\n<\/ol>\n

                                                                                    C\u00e2u 30:<\/u><\/strong> \u00a0\u00a0Cho h\u00e0m s\u1ed1 f(x)=2x^{2<\/sup>+16cosx-cos2x. T\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a f\u201d(p) l\u00e0 :<\/p>\n}

                                                                                    A. 24 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 4 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. -16 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.-8<\/p>\n

                                                                                    C\u00e2u 31:<\/u><\/strong> \u00a0\u00a0T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn v\u1edbi \u0111\u01b0\u1eddng cong cong ( C):y = x^{2<\/sup>-3x+2 \u00a0t\u1ea1i 1 \u0111i\u1ec3m M \u00ce( C)\u00a0 v\u00e0\u00a0 xM = 1:<\/p>\n}

                                                                                    A. y = – x+1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. y = -x-1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. y = x+1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.y = x-1<\/p>\n

                                                                                    C\u00e2u 32:<\/u><\/strong> \u00a0\u00a0Cho 1 parabol (P):y = -x^{2<\/sup>+4x . T\u00ecm h\u1ec7 s\u1ed1 c\u1ee7a ti\u1ebfp tuy\u1ebfn v\u1edbi (P) t\u1ea1i \u0111i\u1ec3m A (1;3):<\/p>\n}

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                                                                                    1. 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. -2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. -3<\/li>\n<\/ol>\n

                                                                                       <\/u>C\u00e2u 33<\/u><\/strong>:<\/u> Cho 1 chuy\u1ec3n \u0111\u1ed9ng th\u1eb3ng c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh \u00a0, \u00a0c\u00f3 t \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng gi\u00e2y, S \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng m\u00e9t. T\u00ecm v\u1eadn t\u1ed1c c\u1ee7a chuy\u1ec3n \u0111\u1ed9ng n\u00e0y khi t=1s:<\/p>\n

                                                                                       \n
                                                                                       1. 7m\/s ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 24m\/s ;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 8m\/s ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 23m\/s .<\/li>\n<\/ol>\n

                                                                                          C\u00e2u 34:<\/u><\/strong> Cho 1 chuy\u1ec3n \u0111\u1ed9ng th\u1eb3ng c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh S= 2t\u00b3 – t + 1\u00a0\u00a0, c\u00f3 t \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng gi\u00e2y, S \u0111\u01b0\u1ee3c t\u00ednh b\u1eb1ng m\u00e9t. T\u00ecm gia t\u1ed1c c\u1ee7a chuy\u1ec3n \u0111\u1ed9ng n\u00e0y khi t=2s:<\/p>\n

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                                                                                          1. 24m\/s2<\/sup>\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 23m\/s2<\/sup> ;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 63m\/s2<\/sup> ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 64m\/s2<\/sup> .<\/li>\n<\/ol>\n

                                                                                             C\u00e2u 35:<\/u><\/strong> Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng \u00a0. Cho bi\u1ebft \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 tri\u1ec7t ti\u00eau t\u1ea1i c\u00e1c \u0111i\u1ec3m l\u00e0 :<\/p>\n

                                                                                             A. x=1 v\u00e0 x= -3 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.x=1 v\u00e0 x=3 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. x= -1 v\u00e0\u00a0 x=3; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. x=0.<\/p>\n

                                                                                             C\u00e2u 36:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 \u00a0. T\u00ednh :<\/p>\n

                                                                                             \n
                                                                                             1. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. -1 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 0 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 2 .<\/li>\n<\/ol>\n

                                                                                                C\u00e2u 37:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 sau: \u00a0\u00a0t\u1ea1i \u0111i\u1ec3m \u00a0x_{0 <\/sub>= 8 g\u1ea7n nh\u1ea5t v\u1edbi s\u1ed1 n\u00e0o:<\/p>\n}

                                                                                                \n
                                                                                                1. 0,5 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0B. 0 ;\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. 0,1 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. 1 .<\/li>\n<\/ol>\n

                                                                                                   C\u00e2u 38<\/u><\/strong>: X\u00e9t 1 h\u00e0m s\u1ed1 . T\u00ecm ph\u01b0\u01a1ng tr\u00ecnh ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 n\u00e0y t\u1ea1i \u0111i\u1ec3m c\u00f3 ho\u00e0nh \u0111\u1ed9 :<\/p>\n

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                                                                                                   1. y = 8x-17\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. y=8x+31 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. y=8x -31 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. y= 26x+85 .<\/li>\n<\/ol>\n

                                                                                                      C\u00e2u 39<\/u><\/strong>:<\/u> Cho bi\u1ebft \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 \u00a0c\u00f3 bao nhi\u00eau ti\u1ebfp tuy\u1ebfn c\u00f3 tung \u0111\u1ed9 l\u00e0 :<\/p>\n

                                                                                                      \n
                                                                                                      1. 2 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. 1 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.3 ; \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.4 .<\/li>\n<\/ol>\n

                                                                                                         _{\u00a0<\/sub>C\u00e2u 40: <\/u><\/strong>Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng y = x^{3<\/sup> \u2013 3mx2<\/sup> +(m +1)x\u00a0 – m ( trong \u0111\u00f3 m l\u00e0 tham s\u1ed1 ). A l\u00e0 giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 n\u00e0y v\u1edbi tr\u1ee5c Oy . T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a m \u0111\u1ec3 ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 n\u00e0y t\u1ea1i A vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng c\u00f3 d\u1ea1ng y = 2x \u2013 3:<\/p>\n}}

                                                                                                         \n
                                                                                                         1. 3\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.-3\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. \u0110\u00e1p s\u1ed1 kh\u00e1c \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.1\/2<\/li>\n<\/ol>\n

                                                                                                            C\u00e2u 41:<\/u><\/strong>\u00a0 Cho h\u00e0m s\u1ed1 f(x) = \u00a0\u00a0. M\u1ec7nh \u0111\u1ec1 n\u00e0y sua l\u00e0 m\u1ec7nh \u0111\u1ec1 sai:<\/p>\n

                                                                                                            \n
                                                                                                            1. h\u00e0m s\u1ed1 f kh\u00f4ng c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x_{0<\/sub> = 1\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0C. f(1) = 2<\/li>\n}
                                                                                                            2. h\u00e0m s\u1ed1 f c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x0<\/sub> = 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 f \u2019(1) = f(1)<\/li>\n<\/ol>\n

                                                                                                               C\u00e2u 42: <\/u><\/strong>Cho h\u00e0m s\u1ed1 y = f(x) c\u00f3 f \u2019(2)\u00a0 . T\u00ecm\u00a0\u00a0 \u00a0b\u1eb1ng :<\/p>\n

                                                                                                               \n
                                                                                                               1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.\u00a0\u00a0\u00a0 f \u2019(2) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 2f \u2019(2) \u2013 f(2) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. f(2) \u2013 2f \u2019(2)<\/li>\n<\/ol>\n

                                                                                                                  C\u00e2u 43:<\/u><\/strong> Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng \u00a0. T\u00ecm m\u1ec7nh \u0111\u1ec1 sai:<\/p>\n

                                                                                                                  \n
                                                                                                                  1. \u00a0 f(1) = 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C. H\u00e0m s\u1ed1 f kh\u00f4ng c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x_{0<\/sub> = 1<\/li>\n}
                                                                                                                  2. \u00a0 f \u2019(1) = 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. h\u00e0m s\u1ed1 f \u00a0li\u00ean t\u1ee5c t\u1ea1i \u0111i\u1ec3m x0<\/sub> = 1<\/li>\n<\/ol>\n

                                                                                                                     C\u00e2u 44 :<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = (x-2)^{3<\/sup>(2x-3)4<\/sup>(3x-4)5<\/sup>\u00a0 t\u1ea1i \u0111i\u1ec3m x_{0<\/sub> = 1 l\u00e0 :<\/p>\n}}

                                                                                                                     \n
                                                                                                                     1. -60 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 -26 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 26 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 60<\/li>\n<\/ol>\n

                                                                                                                        C\u00e2u 45:<\/u><\/strong> \u0110\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = – x \u2013 3\/x + 1\/x\u00b2 d\u01b0\u01a1ng khi v\u00e0 ch\u1ec9 khi ta c\u00f3:<\/p>\n

                                                                                                                        \n
                                                                                                                        1. x < -2 hay x > 0 \u00a0 \u00a0 \u00a0 B.\u00a0 x > 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 x > 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 -2 < x < 0<\/li>\n<\/ol>\n

                                                                                                                           C\u00e2u 46:<\/u><\/strong> T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a x \u0111\u1ec3 \u0111\u1ea1o h\u00e0m h\u00e0m s\u1ed1 y= \u00a0\u00a0 b\u1eb1ng 0:<\/p>\n

                                                                                                                           \n
                                                                                                                           1. 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.\u00a0 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 3<\/li>\n<\/ol>\n

                                                                                                                              C\u00e2u 47:<\/u><\/strong> \u0110\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 y = ln(cotx + 1\/sinx) l\u00e0 1 h\u00e0m s\u1ed1 m\u00e0 gi\u00e1 tr\u1ecb h\u00e0m s\u1ed1 \u0111\u00f3 :<\/p>\n

                                                                                                                              \n
                                                                                                                              1. Lu\u00f4n lu\u00f4n \u00e2m \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. Lu\u00f4n lu\u00f4n d\u01b0\u01a1ng \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 C\u00f3 \u00e2m,c\u00f3 d\u01b0\u01a1ng\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 D.\u00a0 Kh\u00f4ng \u0111\u1ed5i<\/li>\n<\/ol>\n

                                                                                                                                 C\u00e2u 48:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) = \u00a0\u00a0T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a m \u0111\u1ec3 h\u00e0m s\u1ed1 f(x) c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x = 1:<\/p>\n

                                                                                                                                 \n
                                                                                                                                 1. m = 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. m = -1 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 C. m = 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. Kh\u00f4ng c\u00f3<\/li>\n<\/ol>\n

                                                                                                                                    C\u00e2u 49: <\/u><\/strong>Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) = \u00a0. M\u1ec7nh \u0111\u1ec1 n\u00e0o sau \u0111\u00e2y \u0111\u00fang:<\/p>\n

                                                                                                                                    \n
                                                                                                                                    1. f \u2019(0) = 3\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. f \u2018(1) = \u00a0\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. 4.f(1) = 3.f \u2019(1) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 2.f(2) = 3.f \u2018(2)<\/li>\n<\/ol>\n

                                                                                                                                       C\u00e2u 50:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1\u00a0 y = \u00a0t\u1ea1i x_{0<\/sub> = p\/2:<\/p>\n}

                                                                                                                                       \n
                                                                                                                                       1. -1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 -1\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 1\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 1<\/li>\n<\/ol>\n

                                                                                                                                          C\u00e2u 51:<\/u><\/strong> Cho 1 h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) = . Th\u00ec ph\u01b0\u01a1ng tr\u00ecnh f \u2019(x) = x c\u00f3 nghi\u1ec7m thu\u1ed9c kho\u1ea3ng :<\/p>\n

                                                                                                                                          \n
                                                                                                                                          1. (0;1) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 (1;2) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 (2;3) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. M\u1ed9t kho\u1ea3ng kh\u00e1c<\/li>\n<\/ol>\n

                                                                                                                                             C\u00e2u 52 :<\/u><\/strong> T\u00ecm s\u1ed1 gia h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng y = x^{3<\/sup> + 3x2<\/sup> -2x + 1 khi t\u1ea1i \u0111i\u1ec3m x cho s\u1ed1 gia Dx \u00b9 0:<\/p>\n}

                                                                                                                                             \n
                                                                                                                                             1. (3x^{2<\/sup> +6x \u2013 2) \u0394x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 \u03943<\/sup>x + (3x+3) \u03942<\/sup>x + (3x2<\/sup> +6x \u2013 2) \u0394x<\/li>\n}
                                                                                                                                             2. (3x+3) \u03943<\/sup>x + (3x2<\/sup> +6x \u2013 2) \u0394x \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 3x2<\/sup> + 6x – 2<\/li>\n<\/ol>\n

                                                                                                                                                C\u00e2u 53:<\/u><\/strong>\u00a0 \u0110\u1ea1o h\u00e0m 1 h\u00e0m s\u1ed1 \u00a0c\u00f3 d\u1ea1ng y = \u00a0 \u00a0 \u00a0:<\/p>\n

                                                                                                                                                \n
                                                                                                                                                1. lu\u00f4n d\u01b0\u01a1ng \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. lu\u00f4n \u00e2m \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 d\u01b0\u01a1ng khi x > 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 d\u01b0\u01a1ng khi x < 0<\/li>\n<\/ol>\n

                                                                                                                                                   C\u00e2u 54:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) =\u00a0 \u00a0\u00a0t\u1ea1i \u0111i\u1ec3m x = 0 l\u00e0 :<\/p>\n

                                                                                                                                                   \n
                                                                                                                                                   1. 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 4<\/li>\n<\/ol>\n

                                                                                                                                                      C\u00e2u 55:<\/u><\/strong> T\u00ecm \u0111\u1ea1o h\u00e0m h\u00e0m s\u1ed1\u00a0 y = xlnx:<\/p>\n

                                                                                                                                                      \n
                                                                                                                                                      1. xlnx(lnx + 1) \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B.\u00a0 xlnx-1<\/sup>.lnx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. xlnx. lnx \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 2xlnx-1<\/sup>.lnx<\/li>\n<\/ol>\n

                                                                                                                                                         <\/u>C\u00e2u 56: <\/u><\/strong>Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng y = |x^{2<\/sup> + x – 2| . T\u00ecm m\u1ec7nh \u0111\u1ec1 \u0111\u00fang :<\/p>\n}

                                                                                                                                                         \n
                                                                                                                                                         1. f \u2018(-2) = 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 f \u2018(1) = -3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 f \u2018(0) = 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 f \u2018(-1\/2) = 0<\/li>\n<\/ol>\n

                                                                                                                                                            C\u00e2u 57 :<\/u><\/strong> T\u00ecm nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh y\u2019. v\u1edbi y = 2x + 1 bi\u1ebft\u00a0 y = \u00a0\u00a0:<\/p>\n

                                                                                                                                                            \n
                                                                                                                                                            1. Kh\u00f4ng c\u00f3 nghi\u1ec7m \u00a0 B.\u00a0 x = -1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C.\u00a0 x = 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 x = 2<\/li>\n<\/ol>\n

                                                                                                                                                               C\u00e2u 58 :<\/u><\/strong> \u0110\u1ea1o h\u00e0m c\u1ee7a h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng y = ln[ln(lnx)] x\u00e1c \u0111\u1ecbnh v\u1edbi m\u1ecdi x th\u1ecfa \u0111i\u1ec1u ki\u1ec7n :<\/p>\n

                                                                                                                                                               \n
                                                                                                                                                               1. x > 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 x > 1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 x > e \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D.\u00a0 \u0110\u00e1p \u00e1n kh\u00e1c<\/li>\n<\/ol>\n

                                                                                                                                                                  C\u00e2u 59:<\/u><\/strong> Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) = \u00a0T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a a, b \u0111\u1ec3 h\u00e0m s\u1ed1 f(x) c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x = 1:<\/p>\n

                                                                                                                                                                  \n
                                                                                                                                                                  1. a=3\/8, b=1\/4 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. a=4\/3, b=1 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0C. a=1\/4, b=3\/8 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. Kh\u00f4ng c\u00f3<\/li>\n<\/ol>\n

                                                                                                                                                                     C\u00e2u 60 :<\/u><\/strong> Cho h\u00e0m s\u1ed1 c\u00f3 d\u1ea1ng f(x) = \u00a0T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a m \u0111\u1ec3 h\u00e0m s\u1ed1 f(x) c\u00f3 \u0111\u1ea1o h\u00e0m t\u1ea1i \u0111i\u1ec3m x = 0:<\/p>\n

                                                                                                                                                                     \n
                                                                                                                                                                     1. \u2013 1\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B.\u00a0 0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 C.\u00a0 1\/2 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D.\u00a0 Kh\u00f4ng c\u00f3<\/li>\n<\/ol>\n

                                                                                                                                                                        Tr\u00ea \u0111\u00e2y l\u00e0 m\u1ed9t s\u1ed1 c\u00e2u h\u1ecfi tr\u1eafc nghi\u1ec7m b\u00e0i t\u1eadp \u0111\u1ea1o h\u00e0m, hi v\u1ecdng\u00a0c\u00f3 th\u1ec3 gi\u00fap b\u1ea1n nhi\u1ec1u h\u01a1n trong qu\u00e1 tr\u00ecnh \u00f4n thi trung h\u1ecdc ph\u1ed5 th\u00f4ng s\u1eafp t\u1edbi. Ch\u00fac c\u00e1c b\u1ea1n th\u00e0nh c\u00f4ng<\/p>\n","protected":false},"excerpt":{"rendered":"

                                                                                                                                                                        D\u01b0\u1edbi \u0111\u00e2y ch\u00fang t\u00f4i t\u1ed5ng h\u1ee3p m\u1ed9t s\u1ed1 c\u00e2u h\u1ecfi tr\u1eafc nghi\u1ec7m b\u00e0i t\u1eadp \u0111\u1ea1o h\u00e0m \u0111\u1ec3 c\u00e1c h\u1ecdc sinh c\u00f3 th\u1ec3 tham kh\u1ea3o v\u00e0 r\u00e8n luy\u1ec7n th\u00eam c\u00e1c k\u1ef9… <\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[450,469],"tags":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/10396"}],"collection":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/comments?post=10396"}],"version-history":[{"count":0,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/10396\/revisions"}],"wp:attachment":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media?parent=10396"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/categories?post=10396"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/tags?post=10396"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}