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{"id":5123,"date":"2017-12-19T08:54:43","date_gmt":"2017-12-19T01:54:43","guid":{"rendered":"https:\/\/onthitot.com\/?p=5123"},"modified":"2018-12-09T22:22:54","modified_gmt":"2018-12-09T15:22:54","slug":"phuong-phap-giai-bai-tap-xac-dinh-cong-thuc-hoa-hoc","status":"publish","type":"post","link":"https:\/\/onthitot.com\/phuong-phap-giai-bai-tap-xac-dinh-cong-thuc-hoa-hoc\/","title":{"rendered":"PH\u01af\u01a0NG PH\u00c1P GI\u1ea2I B\u00c0I T\u1eacP X\u00c1C \u0110\u1ecaNH C\u00d4NG TH\u1ee8C H\u00d3A H\u1eccC"},"content":{"rendered":"

PH\u01af\u01a0NG PH\u00c1P GI\u1ea2I B\u00c0I T\u1eacP X\u00c1C \u0110\u1ecaNH C\u00d4NG TH\u1ee8C H\u00d3A H\u1eccC<\/strong><\/h2>\n

D\u1ea1ng 1. L\u1eadp c\u00f4ng th\u1ee9c khi bi\u1ebft th\u00e0nh ph\u1ea7n c\u00e1c nguy\u00ean t\u1ed1 v\u00e0 h\u00f3a tr\u1ecb c\u1ee7a ch\u00fang.<\/em><\/strong><\/p>\n

C\u00e1ch gi\u1ea3i<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c d\u1ea1ng chung<\/p>\n

– \u00c1p d\u1ee5ng quy t\u1eafc h\u00f3a tr\u1ecb ta c\u00f3 a.x = b.y<\/p>\n

( a l\u00e0 h\u00f3a tr\u1ecb c\u1ee7a A, b l\u00e0 h\u00f3a tr\u1ecb c\u1ee7a B; B c\u00f3 th\u1ec3 l\u00e0 nh\u00f3m nguy\u00ean t\u1eed)<\/p>\n

+ N\u1ebfu a = b th\u00ec c\u00f4ng th\u1ee9c l\u00e0 AB<\/p>\n

+ N\u1ebfu a # b ; Ta c\u00f3<\/p>\n

Ch\u1ecdn a\u2019, b\u2019 l\u00e0 nh\u1ee9ng s\u1ed1 nguy\u00ean d\u01b0\u01a1ng v\u00e0 t\u1ec9 l\u1ec7 \u00a0l\u00e0 t\u1ed1i gi\u1ea3n<\/p>\n

Suy ra x = b ho\u1eb7c b\u2019; y = a ho\u1eb7c a\u2019<\/p>\n

B\u00e0i t\u1eadp h\u00f3a h\u1ecdc x\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc<\/em><\/h3>\n

<\/p>\n

<\/h3>\n

V\u00ed d\u1ee5 2<\/em><\/strong>: L\u1eadp c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a Ca c\u00f3 h\u00f3a tr\u1ecb II v\u00e0 g\u1ed1c SO4<\/sub>\u00a0C\u00f3 h\u00f3a tr\u1ecb II.<\/strong><\/p>\n

H\u1ecdc sinh v\u1eadn d\u1ee5ng<\/em><\/strong><\/p>\n

C\u00e1ch 1<\/em><\/strong>.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/strong><\/p>\n

–\u00a0<\/strong>\u00a0\u00a0Vi\u1ebft c\u00f4ng th\u1ee9c d\u01b0\u1edbi d\u1ea1ng: CaII<\/sup>x<\/sub>(SO4<\/sub>)II<\/sup>y<\/sub>\u00a0ta c\u00f3: x.II = y.II<\/p>\n

Ta c\u00f3 t\u1ef7 l\u1ec7 =><\/p>\n

– Ch\u1ecdn x = 1; y = 1 ta c\u00f3 c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u00e0: CaSO4<\/sub>.<\/p>\n

C\u00e1ch 2<\/em><\/strong>. \u00a0\u00a0\u00a0\u00a0\u00a0 – T\u1eeb t\u1ef7 l\u1ec7:\u00a0 \u00a0ta c\u00f3 th\u1ec3 t\u00ednh nh\u1ea9m<\/p>\n

– Khi a = b th\u00ec x = y =1 = > c\u00f4ng th\u1ee9c CaSO4<\/sub><\/p>\n

(*)C\u00f3 th\u1ec3 \u00e1p d\u1ee5ng c\u00e1ch 2 \u0111\u1ec3 t\u00ednh nh\u1ea9m cho m\u1ed9t s\u1ed1 c\u00e1c tr\u01b0\u1eddng h\u1ee3p sau \u0111\u00e2y<\/strong><\/p>\n

– Khi a = b th\u00ec x = y = 1<\/p>\n

+ H\u1ee3p ch\u1ea5t<\/p>\n

x = y = 1 V\u1eady c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u00e0: MgO<\/p>\n

+ H\u1ee3p ch\u1ea5t\u00a0 \u00a0\u00a0\u00a0\u00a0x = y = 1<\/p>\n

V\u1eady c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u00e0: AlPO4<\/sub><\/p>\n

– Khi a = I th\u00ec x = b v\u00e0 y = 1 ho\u1eb7c b = I th\u00ec x = 1 v\u00e0 y = a.<\/p>\n

x = 2; y = 1.<\/p>\n

V\u1eady c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc l\u00e0: Na2<\/sub>O<\/p>\n

– Khi a > b \u0111\u1ec1u l\u00e0 s\u1ed1 ch\u1eb5n \u00a0\u00a0\u00a0x = 1 v\u00e0 y = a\u00a0: b<\/p>\n

ta c\u00f3 \u00a0\u00a0\u00a0CO2<\/sub><\/p>\n

ta c\u00f3 \u00a0\u00a0\u00a0\u00a0SO3<\/sub><\/p>\n

– Khi a\u00a0 \u00a0\u00a0b v\u00e0\u00a0 \u0111\u1ec1u\u00a0\u00a0 \u00a0\u00a02 th\u00ec x = b v\u00e0 y = a.<\/p>\n

N\u1ebfu c\u1ea3 x v\u00e0 y \u0111\u1ec1u l\u00e0 s\u1ed1 ch\u1eb5n ho\u1eb7c c\u00f3 \u01b0\u1edbc s\u1ed1 chung th\u00ec r\u00fat g\u1ecdn l\u1ea5y s\u1ed1 \u0111\u01a1n gi\u1ea3n nh\u1ea5t.<\/p>\n

D\u1ea1ng 2. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc d\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 ph\u00e2n t\u00edch \u0111\u1ecbnh l\u01b0\u1ee3ng<\/strong><\/p>\n

<\/span>\u00a0D2.1<\/u><\/strong>. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc khi bi\u1ebft th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u00e1c nguy\u00ean t\u1ed1 v\u00e0 ph\u00e2n t\u1eed kh\u1ed1i.<\/strong><\/p>\n

C\u00e1ch gi\u1ea3i<\/strong><\/p>\n

– Gi\u1ea3 s\u1eed c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Ax<\/sub>By,\u00a0<\/sub>bi\u1ebft %A v\u00e0 %B. C\u1ea7n t\u00ecm x v\u00e0 y<\/p>\n

– T\u00ecm kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i nguy\u00ean t\u1ed1 trong h\u1ee3p ch\u1ea5t<\/p>\n

mA<\/sub>\u00a0= \u00a0 mB =\u00a0<\/sub>\u00a0( ho\u1eb7c mB =\u00a0<\/sub>– mA<\/sub>\u00a0\u00a0)<\/sub><\/p>\n

– T\u00ecm s\u1ed1 mol nguy\u00ean t\u1eed m\u1ed7i nguy\u00ean t\u1ed1 trong 1 mol h\u1ee3p ch\u1ea5t<\/p>\n

– Ch\u1ecdn x = a, y = b\u00a0 => suy ra c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t<\/p>\n

( L\u01b0u \u00fd trong c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t hai nguy\u00ean t\u1ed1<\/em><\/p>\n

– N\u1ebfu m\u1ed9t nguy\u00ean t\u1ed1 l\u00e0 Oxi th\u00ec Oxi lu\u00f4n lu\u00f4n \u0111\u1ee9ng sau<\/em><\/p>\n

– N\u1ebfu m\u1ed9t nguy\u00ean t\u1ed1 l\u00e0 kim lo\u1ea1i, m\u1ed9t nguy\u00ean t\u1ed1 l\u00e0 phi kim th\u00ec kim lo\u1ea1i lu\u00f4n lu\u00f4n \u0111\u1ee9ng tr\u01b0\u1edbc<\/em><\/p>\n

– Trong tr\u01b0\u1eddng h\u1ee3p b\u00e0i to\u00e1n cho t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed th\u00ec d\u1ef1a v\u00e0o t\u1ec9 kh\u1ed1i ch\u1ea5t kh\u00ed \u0111\u1ec3 t\u00ecm kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a ch\u1ea5t c\u1ea7n t\u00ecm theo CT: MA<\/sub>\u00a0= dA\/B\u00a0<\/sub>. MB<\/sub>\u00a0ho\u1eb7c\u00a0\u00a0\u00a0 MA<\/sub>\u00a0= dA\/KK\u00a0<\/sub>. 29\u00a0 )<\/em><\/p>\n

V\u00ed d\u1ee5 1<\/u><\/em><\/strong>:<\/em><\/strong>\u00a0H\u1ee3p ch\u1ea5t X c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng 62 \u0111vC. Trong ph\u00e2n t\u1eed c\u1ee7a h\u1ee3p ch\u1ea5t nguy\u00ean t\u1ed1 oxi chi\u1ebfm 25,8% theo kh\u1ed1i l\u01b0\u1ee3ng, c\u00f2n l\u1ea1i l\u00e0 nguy\u00ean t\u1ed1 Na. L\u1eadp c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a X?<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a X l\u00e0 Nax<\/sub>Oy<\/sub><\/p>\n

– Kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i nguy\u00ean t\u1ed1 trong h\u1ee3p ch\u1ea5t l\u00e0<\/p>\n

– Trong m\u1ed9t mol ph\u00e2n t\u1eed h\u1ee3p ch\u1ea5t X c\u00f3<\/p>\n

– Ta c\u00f3<\/p>\n

Suy ra c\u00f4ng th\u1ee9c c\u1ee7a X l\u00e0 Na2<\/sub>O<\/p>\n

V\u00ed d\u1ee5 2.<\/em><\/strong>\u00a0T\u00ecm c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t khi bi\u1ebft th\u00e0nh ph\u1ea7n kh\u1ed1i l\u01b0\u1ee3ng nh\u01b0 sau:\u00a0 2,4% H,\u00a0 39,1% S v\u00e0\u00a0 58,5% O. Bi\u1ebft ph\u00e2n t\u1eed kh\u1ed1i l\u00e0 82 \u0111vC.<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ea7n t\u00ecm l\u00e0 Hx<\/sub>Sy<\/sub>Oz<\/sub><\/p>\n

Ta c\u00f3 x + 32y + 16z = 82<\/p>\n

– L\u1eadp kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i nguy\u00ean t\u1ed1 trong h\u1ee3p ch\u1ea5t<\/p>\n

– T\u00ecm s\u1ed1 mol nguy\u00ean t\u1eed c\u1ee7a t\u1eebng nguy\u00ean t\u1ed1<\/p>\n

nH\u00a0\u00a0<\/sub>= 2 : 1\u00a0 \u00a0\u00a0= 2 (mol)<\/p>\n

nS\u00a0\u00a0<\/sub>= 32 : 32 = 1 (mol)<\/p>\n

nO\u00a0\u00a0<\/sub>= 48 : 16 = 3(mol)<\/p>\n

=> x = 2, y = 1, z = 3<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 H2<\/sub>SO3<\/sub><\/p>\n

V\u00ed d\u1ee5 3:<\/em><\/strong>\u00a0X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc m\u1ed9t oxit c\u1ee7a l\u01b0u hu\u1ef3nh bi\u1ebft ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a oxit \u0111\u00f3 l\u00e0 80 v\u00e0 trong \u0111\u00f3 S chi\u1ebfm 40% v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng?<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

\u00a0C\u00e1ch 1<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Sx<\/sub>Oy<\/sub><\/p>\n

– T\u00ecm s\u1ed1 mol nguy\u00ean t\u1eed m\u1ed7i nguy\u00ean t\u1ed1 trong 1 mol h\u1ee3p ch\u1ea5t<\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 => x = 1. y = 3<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ea7n t\u00ecm l\u00e0 S03<\/sub>.<\/p>\n

C\u00e1ch 2<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Sx<\/sub>Oy<\/sub><\/p>\n

– T\u00ecm t\u1ec9 l\u1ec7 kh\u1ed1i l\u01b0\u1ee3ng c\u00e1c nguy\u00ean t\u1ed1. V\u00ec kh\u1ed1i l\u01b0\u1ee3ng m\u1ed7i nguy\u00ean t\u1ed1 trong ph\u00e2n t\u1eed t\u1ec9 l\u1ec7 v\u1edbi th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m n\u00ean ta c\u00f3:<\/p>\n

\u00a0\u00a0\u00a0\u00a0 => x =1, y = 3.<\/p>\n

– C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ea7n t\u00ecm l\u00e0 SO3<\/sub>.<\/p>\n

C\u00e1ch 3<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Sx<\/sub>Oy<\/sub><\/p>\n

–\u00a0 L\u1eadp t\u1ec9 s\u1ed1 v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng \u0111\u1ec3 t\u00ecm x,y<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c l\u00e0 SO3<\/sub><\/p>\n

V\u00ed d\u1ee5 4.<\/em>\u00a0Ph\u00e2n t\u1eed h\u1ee3p ch\u1ea5t D c\u00f3 t\u1ec9 kh\u1ed1i \u0111\u1ed1i v\u1edbi kh\u00ed hi\u0111ro b\u1eb1ng 17. Bi\u1ebft trong D, H chi\u1ebfm 5,88 % v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng, c\u00f2n l\u1ea1i l\u00e0 L\u01b0u hu\u1ef3nh. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c ph\u00e2n t\u1eed c\u1ee7a D.<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– T\u00ednh kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a h\u1ee3p ch\u1ea5t<\/p>\n

=> MA<\/sub>\u00a0= 17.2 = 34 (g)<\/p>\n

– Sau \u0111\u00f3 c\u00f3 th\u1ec3 l\u00e0m theo 1 trong 3 c\u00e1ch gi\u1ed1ng nh\u01b0 v\u00ed d\u1ee5 3 \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 H2<\/sub>S.<\/p>\n

D2.2<\/u>. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc khi bi\u1ebft th\u00e0nh ph\u1ea7n ph\u1ea7n tr\u0103m v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng m\u00e0 kh\u00f4ng bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a h\u1ee3p ch\u1ea5t.<\/strong><\/p>\n

C\u00e1ch gi\u1ea3i<\/em><\/strong><\/p>\n

– C\u00f4ng th\u1ee9c chung c\u1ee7a h\u1ee3p ch\u1ea5t d\u1ea1ng Ax<\/sub>By\u00a0<\/sub>ho\u1eb7c Ax<\/sub>By<\/sub>Cz\u2026<\/sub><\/p>\n

( trong \u0111\u00f3 a,b,c l\u00e0 nh\u1eefng s\u1ed1 nguy\u00ean d\u01b0\u01a1ng, t\u1ed1i gi\u1ea3n)<\/p>\n

– Ch\u1ecdn x = a, y = b, z = c\u00a0 => Suy ra c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t.<\/p>\n

\u00a0V\u00ed d\u1ee5 1<\/em>: Khi ph\u00e2n t\u00edch m\u1ed9t mu\u1ed1i ch\u1ee9a 52,35%K\u00a0 v\u00e0 47,65% Cl v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a mu\u1ed1i tr\u00ean?<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Kx<\/sub>Cly<\/sub><\/p>\n

Ta c\u00f3:<\/p>\n

– Suy ra c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t mu\u1ed1i c\u1ea7n t\u00ecm l\u00e0 KCl<\/p>\n

V\u00ed d\u1ee5 2.\u00a0<\/em>Ph\u00e2n t\u00edch m\u1ed9t h\u1ee3p ch\u1ea5t v\u00f4 c\u01a1 A c\u00f3 th\u00e0nh ph\u1ea7n % theo kh\u1ed1i l\u01b0\u1ee3ng nh\u01b0 sau: Cu chi\u1ebfm 40 %, S chi\u1ebfm 20 % v\u00e0 O chi\u1ebfm 40%. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a A?<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Cux<\/sub>Sy<\/sub>Oz<\/sub><\/p>\n

– Ta c\u00f3\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x : y : z =<\/p>\n

=> \u00a0\u00a0\u00a0\u00a0\u00a0x : y: z =<\/p>\n

x : y : z = 0,625 : 0,625 : 2,5<\/p>\n

=>\u00a0\u00a0\u00a0\u00a0\u00a0 x: y: z = 1 : 1: 4<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c c\u1ee7a A l\u00e0 CuSO4<\/sub><\/p>\n

D2.3.\u00a0<\/u><\/strong>\u00a0X\u00e1c \u0111inh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc khi bi\u1ebft t\u1ec9 l\u1ec7 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a c\u00e1c nguy\u00ean t\u1ed1 trong h\u1ee3p ch\u1ea5t.<\/strong><\/p>\n

C\u00e1ch gi\u1ea3i<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ea7n t\u00ecm l\u00e0 Ax<\/sub>By\u00a0<\/sub>, bi\u1ebft t\u1ec9 l\u1ec7 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a A v\u1edbi B l\u00e0 a:b<\/p>\n

Ta c\u00f3: \u00a0(Trong \u0111\u00f3 a\u2019, b\u2019 l\u00e0 c\u00e1c s\u1ed1 nguy\u00ean d\u01b0\u01a1ng, t\u1ed1i gi\u1ea3n)<\/p>\n

=> x = a\u2019, y = b\u2019<\/p>\n

– Suy ra c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t<\/p>\n

\u00a0V\u00ed d\u1ee5 1:<\/em>\u00a0T\u00ecm c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a m\u1ed9t oxit c\u1ee7a s\u1eaft, bi\u1ebft r\u1eb1ng t\u1ef7 l\u1ec7 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a s\u1eaft v\u00e0 oxi l\u00e0 7:3.<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c c\u1ea7n t\u00ecm l\u00e0 Fex<\/sub>Oy<\/sub><\/p>\n

– Ta c\u00f3 :<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c c\u1ee7a oxit s\u1eaft \u0111\u00f3 l\u00e0 Fe2<\/sub>O3<\/sub><\/p>\n

V\u00ed d\u1ee5 2<\/em><\/strong>.<\/em>\u00a0M\u1ed9t h\u1ee3p ch\u1ea5t c\u00f3 t\u1ec9 l\u1ec7 v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a c\u00e1c nguy\u00ean t\u1ed1 Ca: N: O l\u1ea7n l\u01b0\u1ee3t l\u00e0 10:7:24. X\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t bi\u1ebft N v\u00e0 O h\u00ecnh th\u00e0nh nh\u00f3m nguy\u00ean t\u1eed, v\u00e0 trong nh\u00f3m t\u1ec9 l\u1ec7 s\u1ed1 nguy\u00ean t\u1eed c\u1ee7a N: O = 1:3.<\/strong><\/p>\n

H\u01b0\u1edbng d\u1eabn<\/em><\/strong><\/p>\n

– G\u1ecdi c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a h\u1ee3p ch\u1ea5t c\u1ea7n t\u00ecm l\u00e0 Cax<\/sub>Ny<\/sub>Oz<\/sub><\/p>\n

– Ta c\u00f3\u00a0 x : y : z =<\/p>\n

=> \u00a0\u00a0\u00a0 \u00a0\u00a0x : y : z = 1 : 2 : 6<\/p>\n

– V\u00ec trong nh\u00f3m nguy\u00ean t\u1eed, t\u1ec9 l\u1ec7 s\u1ed1 nguy\u00ean t\u1eed N : O = 1 : 3<\/p>\n

Ta c\u00f3 nh\u00f3m (NO3<\/sub>)n<\/sub>\u00a0v\u00e0\u00a0 3. n = 6 => n =2<\/p>\n

– V\u1eady c\u00f4ng th\u1ee9c c\u1ee7a h\u1ee3p ch\u1ea5t l\u00e0 Ca(NO3<\/sub>)2.<\/sub><\/p>\n

Tr\u00ean \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p gi\u1ea3i b\u00e0i t\u1eadp h\u00f3a h\u1ecdc x\u00e1c \u0111\u1ecbnh c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc v\u00e0 m\u1ed9t s\u1ed1 b\u00e0i t\u1eadp minh h\u1ecda, c\u00e1c b\u1ea1n tham kh\u1ea3o nh\u00e9.<\/p>\n","protected":false},"excerpt":{"rendered":"

PH\u01af\u01a0NG PH\u00c1P GI\u1ea2I B\u00c0I T\u1eacP X\u00c1C \u0110\u1ecaNH C\u00d4NG TH\u1ee8C H\u00d3A H\u1eccC D\u1ea1ng 1. L\u1eadp c\u00f4ng th\u1ee9c khi bi\u1ebft th\u00e0nh ph\u1ea7n c\u00e1c nguy\u00ean t\u1ed1 v\u00e0 h\u00f3a tr\u1ecb c\u1ee7a ch\u00fang. C\u00e1ch gi\u1ea3i… <\/p>\n","protected":false},"author":1,"featured_media":5125,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[452,75],"tags":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/5123"}],"collection":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/comments?post=5123"}],"version-history":[{"count":0,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/5123\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media\/5125"}],"wp:attachment":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media?parent=5123"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/categories?post=5123"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/tags?post=5123"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}