\u00a0B\u1ed9 \u0111\u1ec1 thi h\u1ecdc k\u00ec 2 m\u00f4n To\u00e1n l\u1edbp 5<\/span><\/h2>\n

<\/h3>\n

I. TR\u1eaeC NGHI\u1ec6M (6 \u0111i\u1ec3m)<\/strong><\/h2>\n

Ch\u1ecdn \u00fd \u0111\u00fang ghi v\u00e0o b\u00e0i l\u00e0m. (C\u00e2u 1; 2; 3; 4; 5; 7).<\/strong><\/p>\n

C\u00e2u 1<\/strong>.<\/strong>\u00a0(0,5 \u0111i\u1ec3m)<\/strong>\u00a0S\u1ed1 b\u00e9 nh\u1ea5t trong c\u00e1c s\u1ed1: 3,055; 3,050; 3,005; 3,505 l\u00e0:<\/p>\n

a. 3,505<\/p>\n

b. 3,050<\/p>\n

c. 3,005<\/p>\n

d. 3,055<\/p>\n

C\u00e2u 2<\/strong>.\u00a0<\/strong>(0,5 \u0111i\u1ec3m)<\/strong>\u00a0Trung b\u00ecnh m\u1ed9t ng\u01b0\u1eddi th\u1ee3 l\u00e0m m\u1ed9t s\u1ea3n ph\u1ea9m h\u1ebft 1gi\u1edd 30 ph\u00fat. Ng\u01b0\u1eddi \u0111\u00f3 l\u00e0m 5 s\u1ea3n ph\u1ea9m m\u1ea5t bao l\u00e2u?<\/p>\n

a. 7 gi\u1edd 30 ph\u00fat<\/p>\n

b. 7 gi\u1edd 50 ph\u00fat<\/p>\n

c. 6 gi\u1edd 50 ph\u00fat<\/p>\n

d. 6 gi\u1edd 15 ph\u00fat<\/p>\n

C\u00e2u 3<\/strong>. (<\/strong>0,5 \u0111i\u1ec3m)<\/strong>\u00a0C\u00f3 bao nhi\u00eau s\u1ed1 th\u1eadp ph\u00e2n \u1edf gi\u1eefa 0,5 v\u00e0 0,6:<\/p>\n

a. Kh\u00f4ng c\u00f3 s\u1ed1 n\u00e0o<\/p>\n

b.\u00a0<\/strong>1 s\u1ed1<\/p>\n

c. 9 s\u1ed1<\/p>\n

d. R\u1ea5t nhi\u1ec1u s\u1ed1<\/p>\n

C\u00e2u 4<\/strong>.<\/strong>\u00a0(0,5 \u0111i\u1ec3m)\u00a0<\/strong>H\u1ed7n s\u1ed1 3vi\u1ebft th\u00e0nh s\u1ed1 th\u1eadp ph\u00e2n l\u00e0:<\/p>\n

a. 3,90<\/p>\n

b.3,09<\/p>\n

c.3,9100<\/p>\n

d. 3,109<\/p>\n

C\u00e2u 5<\/strong>. (1 \u0111i\u1ec3m)<\/strong>\u00a0T\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft 20 % c\u1ee7a n\u00f3 l\u00e0 16. S\u1ed1 \u0111\u00f3 l\u00e0:<\/p>\n

a. 0,8<\/p>\n

b. 8<\/p>\n

c. 80<\/p>\n

d. 800<\/p>\n

C\u00e2u 6.<\/strong>\u00a0<\/strong>(1 \u0111i\u1ec3m)<\/strong>\u00a0\u0110\u00fang \u0111i\u1ec1n \u0110, sai \u0111i\u1ec1n S v\u00e0o \u00f4 tr\u1ed1ng.<\/p>\n

M\u1ed9t h\u00ecnh l\u1eadp ph\u01b0\u01a1ng c\u00f3 di\u1ec7n t\u00edch xung quanh l\u00e0 36 dm^{2<\/sup>. Th\u1ec3 t\u00edch h\u00ecnh l\u1eadp ph\u01b0\u01a1ng \u0111\u00f3 l\u00e0:<\/p>\n}

a. 27 dm^{3<\/sup><\/p>\n}

b. 2700 cm^{3<\/sup><\/p>\n}

c. 54 dm^{3<\/sup><\/p>\n}

d. 27000 cm^{3<\/sup><\/p>\n}

C\u00e2u 7.<\/strong>\u00a0(1 \u0111i\u1ec3m)<\/strong>\u00a0Trong c\u00e1c v\u1eadn t\u1ed1c sau, v\u1eadn t\u1ed1c n\u00e0o l\u1edbn nh\u1ea5t?<\/p>\n

a. 810m\/ph\u00fat<\/p>\n

b. 0,78km\/ph\u00fat<\/p>\n

c. 12,5m\/gi\u00e2y<\/p>\n

d. 48km\/gi\u1edd<\/p>\n

C\u00e2u 8<\/strong>. (1 \u0111i\u1ec3m)<\/strong>\u00a0\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 ch\u1ea5m:<\/p>\n

a. 0,48 m^{2<\/sup>\u00a0= \u2026\u2026 cm2<\/sup><\/p>\n}

b. 0,2 kg = \u2026\u2026 g<\/p>\n

c.5628 dm^{3<\/sup>\u00a0= \u2026\u2026m3<\/sup><\/p>\n}

d. 3 gi\u1edd 6 ph\u00fat = \u2026.gi\u1edd<\/p>\n

II. T\u1ef0 LU\u1eacN: ( 4 \u0111i\u1ec3m)<\/strong><\/h3>\n

B\u00e0i 1.<\/strong>\u00a0(2 \u0111i\u1ec3m)<\/strong>\u00a0\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh.<\/p>\n

a. 56,72 + 76,17<\/p>\n

b. 367,21 – 128,82<\/p>\n

c. 3,17 x 4,5<\/p>\n

d. 52,08 :4,2<\/p>\n

B\u00e0i 2<\/strong>. (2 \u0111i\u1ec3m)<\/strong>\u00a0<\/strong>Qu\u00e3ng \u0111\u01b0\u1eddng AB d\u00e0i 180 km. L\u00fac 7 gi\u1edd 30 ph\u00fat, m\u1ed9t \u00f4 t\u00f4 \u0111i t\u1eeb A \u0111\u1ebfn B v\u1edbi v\u1eadn t\u1ed1c 54 km\/gi\u1edd, c\u00f9ng l\u00fac \u0111\u00f3 m\u1ed9t xe m\u00e1y \u0111i t\u1eeb B \u0111\u1ebfn A v\u1edbi v\u1eadn t\u1ed1c 36 km\/gi\u1edd. H\u1ecfi:<\/p>\n

a. Hai xe g\u1eb7p nhau l\u00fac m\u1ea5y gi\u1edd?
\nb. Ch\u1ed7 2 xe g\u1eb7p nhau c\u00e1ch A bao nhi\u00eau ki-l\u00f4-m\u00e9t?<\/p>\n

H\u01b0\u1edbng d\u1eabn \u0111\u00e1nh gi\u00e1, ghi \u0111i\u1ec3m To\u00e1n l\u1edbp 5<\/h3>\n

I.TR\u1eaeC NGHI\u1ec6M (6 \u0111i\u1ec3m)<\/strong><\/p>\n

C\u00e2u 1.<\/strong>\u00a0\u00a0(0,5 \u0111i\u1ec3m)\u00a0<\/strong>\u0111\u00e1p \u00e1n c<\/p>\n

C\u00e2u 2.<\/strong>\u00a0\u00a0(0,5 \u0111i\u1ec3m)\u00a0<\/strong>\u0111\u00e1p \u00e1n a<\/p>\n

C\u00e2u 3<\/strong>.<\/strong>\u00a0<\/strong>( 0,5 \u0111i\u1ec3m)<\/strong>\u00a0\u0111\u00e1p \u00e1n d<\/p>\n

C\u00e2u 4.<\/strong>\u00a0\u00a0(0,5 \u0111i\u1ec3m)\u00a0<\/strong>\u0111\u00e1p \u00e1n b<\/p>\n

C\u00e2u 5<\/strong>.\u00a0<\/strong>(1 \u0111i\u1ec3m)\u00a0<\/strong>\u0111\u00e1p \u00e1n c<\/p>\n

C\u00e2u 6<\/strong>.<\/strong>\u00a0(1 \u0111i\u1ec3m)<\/strong><\/p>\n

a. 27 dm^{3<\/sup>\u00a0 \u0110<\/p>\n}

b. 2700 cm^{3<\/sup>\u00a0S<\/p>\n}

c. 54 dm^{3<\/sup>\u00a0S<\/p>\n}

d. 27000 cm^{3\u00a0<\/sup>\u0110<\/p>\n}

C\u00e2u 6.<\/strong>\u00a0(1 \u0111i\u1ec3m)<\/strong>\u00a0\u0111\u00e1p \u00e1n c<\/p>\n

C\u00e2u 7.<\/strong>\u00a0(1 \u0111i\u1ec3m)<\/strong>\u00a0\u0111\u00e1p \u00e1n a<\/p>\n

C\u00e2u 8<\/strong>.<\/strong>\u00a0(1 \u0111i\u1ec3m)\u00a0<\/strong>M\u1ed7i \u00fd \u0111\u00fang ghi 0,25 \u0111i\u1ec3m<\/p>\n

a. 0,48 m^{2<\/sup>\u00a0\u00a0= 4800 cm2<\/sup><\/p>\n}

b. 0,2 kg = 200 g<\/p>\n

c. 5628 \u00a0dm^{3<\/sup>\u00a0= 5,628 m3<\/sup><\/p>\n}

d. 3 gi\u1edd 6 ph\u00fat = 3,1.gi\u1edd<\/p>\n

II. T\u1ef0 LU\u1eacN ( 4 \u0111i\u1ec3m)<\/strong><\/p>\n

B\u00e0i 1:<\/strong>\u00a0<\/em><\/strong>(2 \u0111i\u1ec3m\u00a0<\/strong>)\u00a0<\/em><\/strong>\u0110\u1eb7t t\u00ednh v\u00e0 t\u00ednh \u0111\u00fang m\u1ed7i ph\u00e9p t\u00ednh ghi 0,5 \u0111i\u1ec3m<\/p>\n

a. 132,89<\/p>\n

b. 238,39<\/p>\n

c. \u00a014,265<\/p>\n

d. 12,4<\/p>\n

B\u00e0i 2:<\/strong>\u00a0<\/em><\/strong>(2 \u0111i\u1ec3m)\u00a0<\/em><\/strong><\/p>\n

Gi\u1ea3i<\/strong><\/p>\n

T\u1ed5ng hai v\u1eadn t\u1ed1c l\u00e0:<\/em><\/p>\n

36 + 54 = 90 (km\/ gi\u1edd) \u00a0(0,5 \u0111i\u1ec3m)<\/em><\/p>\n

Hai ng\u01b0\u1eddi g\u1eb7p nhau sau:<\/em><\/p>\n

180 : 90 = 2 (gi\u1edd) \u00a0\u00a0(0,5 \u0111i\u1ec3m)<\/em><\/p>\n

Hai ng\u01b0\u1eddi g\u1eb7p nhau l\u00fac:<\/em><\/p>\n

2 gi\u1edd + 7 gi\u1edd 30 ph\u00fat = 9gi\u1edd 30 ph\u00fat \u00a0\u00a0\u00a0(0,5 \u0111i\u1ec3m)<\/em><\/p>\n

Ch\u1ed7 g\u1eb7p nhau c\u00e1ch A s\u1ed1 km l\u00e0:<\/em><\/p>\n

54 x 2 \u00a0= 108 (km) \u00a0\u00a0\u00a0\u00a0\u00a0(0,5 \u0111i\u1ec3m)<\/em><\/p>\n

\u0110\u00e1p s\u1ed1: a) 9 gi\u1edd 30 ph\u00fat<\/em><\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

\u00a0B\u1ed9 \u0111\u1ec1 thi h\u1ecdc k\u00ec 2 m\u00f4n To\u00e1n l\u1edbp 5 I. TR\u1eaeC NGHI\u1ec6M (6 \u0111i\u1ec3m) Ch\u1ecdn \u00fd \u0111\u00fang ghi v\u00e0o b\u00e0i l\u00e0m. (C\u00e2u 1; 2; 3; 4; 5; 7). C\u00e2u… <\/p>\n","protected":false},"author":1,"featured_media":6036,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[413],"tags":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/6035"}],"collection":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/comments?post=6035"}],"version-history":[{"count":0,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/6035\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media\/6036"}],"wp:attachment":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media?parent=6035"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/categories?post=6035"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/tags?post=6035"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}