Trong th\u1ef1c t\u1ebf ta g\u1eb7p r\u1ea5t nhi\u1ec1u b\u00e0i to\u00e1n v\u1ec1 t\u00ednh m3 v\u00ec v\u1eady h\u00f4m nay tamcaotrithuc.com s\u1ebd c\u00f9ng c\u00e1c b\u1ea1n \u00f4n l\u1ea1i c\u00e1c c\u00f4ng th\u1ee9c t\u00ednh m3 v\u00e0 m\u1ed9t s\u1ed1 b\u00e0i t\u1eadp \u0111\u1ec3 c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng c\u00e1c c\u00f4ng th\u1ee9c n\u00e0y m\u1ed9t c\u00e1ch hi\u1ec7u qu\u1ea3 nh\u1ea5t.<\/p>\n

I\/ C\u00f4ng th\u1ee9c t\u00ednh m3<\/strong><\/h2>\n

C\u00e1c c\u00f4ng th\u1ee9c t\u00ednh m3 th\u1ec3 t\u00edch c\u1ee7a v\u1eadt<\/p>\n

1\/ C\u00f4ng th\u1ee9c t\u00ednh m3 theo kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang<\/h3>\n

V = m \/ D<\/p>\n

Trong \u0111\u00f3:<\/p>\n

\n
• D: la\u0300 kh\u00f4\u0301i l\u01b0\u01a1\u0323ng ri\u00eang hay kh\u1ed1i l\u01b0\u1ee3ng cu\u0309a 1 \u0111\u01a1n vi\u0323 th\u00ea\u0309 ti\u0301ch (hay 1 me\u0301t kh\u00f4\u0301i) v\u00e2\u0323t ch\u00e2\u0301t.<\/li>\n
• M: la\u0300 kh\u00f4\u0301i l\u01b0\u01a1\u0323ng v\u00e2\u0323t (kg).<\/li>\n
• V: la\u0300 th\u00ea\u0309 ti\u0301ch c\u1ee7a v\u00e2\u0323t (m\u00b3).<\/li>\n<\/ul>\n

  <\/p>\n

  2\/ C\u00f4ng th\u1ee9c t\u00ednh m3 theo tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang<\/h3>\n

  V = P \/ d<\/p>\n

  Trong \u0111\u00f3:<\/p>\n

  \n
  • d: la\u0300 tro\u0323ng l\u01b0\u01a1\u0323ng ri\u00eang hay tr\u1ecdng l\u01b0\u1ee3ng cu\u0309a 1 \u0111\u01a1n vi\u0323 th\u00ea\u0309 ti\u0301ch (hay 1 me\u0301t kh\u00f4\u0301i) v\u00e2\u0323t ch\u00e2\u0301t.<\/li>\n
  • P: la\u0300 tro\u0323ng l\u01b0\u01a1\u0323ng v\u00e2\u0323t (N).<\/li>\n
  • V: la\u0300 th\u00ea\u0309 ti\u0301ch c\u1ee7a v\u00e2\u0323t (m\u00b3 ).<\/li>\n<\/ul>\n

    II\/ B\u00e0i t\u1eadp \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh m3<\/h2>\n

    1\/ B\u00e0i t\u1eadp \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh m3 c\u00f3 l\u1eddi gi\u1ea3i<\/h3>\n

    D\u01b0\u1edbi \u0111\u00e2y l\u00e0 m\u1ed9t s\u1ed1 b\u00e0i t\u1eadp \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh m3 c\u00f3 h\u01b0\u1edbng d\u1eabn gi\u1ea3i \u0111\u1ec3 c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 n\u1eafm v\u1eefng c\u00e1c c\u00f4ng th\u1ee9c<\/p>\n

    B\u00e0i t\u1eadp 1:<\/strong> Cho bi\u1ebft 10 l\u00edt c\u00e1t c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 15 kg<\/p>\n

    a) H\u00e3y t\u00ednh th\u1ec3 t\u00edch c\u1ee7a 1 t\u1ea5n c\u00e1t.<\/p>\n

    b) H\u00e3y t\u00ednh tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a 1 \u0111\u1ed1ng c\u00e1t l\u00e0 3m^{3<\/sup><\/p>\n}

    <\/p>\n

    T\u00f3m t\u1eaft :<\/strong><\/p>\n

    V = 10 l\u00edt = 0,01 m^{3<\/sup>;<\/p>\n}

    m_{1<\/sub> = 15kg<\/p>\n}

    m_{2 <\/sub>= 1 t\u1ea5n \u00a0= 1000kg<\/p>\n}

    V = ? ;<\/p>\n

    P = ? bi\u1ebft V = 3m^{3<\/sup><\/p>\n}

    Gi\u1ea3i:<\/strong><\/p>\n

    a\/ Ta c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a c\u00e1t l\u00e0 : D = m \/ V = 15 \/ 0,01 = 1500 (kg\/m^{3<\/sup>)<\/p>\n}

    \u00a0\u00a0\u00a0\u00a0 V\u1eady th\u1ec3 t\u00edch 1 t\u1ea5n c\u00e1t l\u00e0: V = m \/ V = 1000 \/ 1500 = 0,667 (m^{3<\/sup>)<\/p>\n}

    b\/ \u0110\u1ed1ng c\u00e1t 3m^{3<\/sup> c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng l\u00e0: P = d x V = 10 x 1500 x 3 = 45000N<\/p>\n}

    B\u00e0i t\u1eadp 2:<\/strong> T\u00ednh \u00a0kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a 1 kh\u1ed1i \u0111\u00e1. Cho bi\u1ebft kh\u1ed1i \u0111\u00e1 \u0111\u00f3 c\u00f3 th\u1ebf t\u00edch 0,5 m^{3<\/sup>.<\/p>\n}

    Gi\u1ea3i:<\/strong><\/p>\n

    \u00a0Theo b\u1ea3ng ta c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a \u0111\u00e1: D = 2600kg\/m^{3<\/sup>.<\/p>\n}

    V\u1eady v\u1edbi 0,5m^{3<\/sup> \u0111\u00e1 th\u00ec ta c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0: m = V.D = 2600.0,5 = 1300kg.<\/p>\n}

    B\u00e0i t\u1eadp 3:<\/strong> X\u00e1c \u0111\u1ecbnh tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t \u0111\u00e3 l\u00e0m qu\u1ea3 c\u00e2n. D\u1ee5ng c\u1ee5 \u0111\u1ec3 l\u00e0m qu\u1ea3 c\u00e2n g\u1ed3m c\u00f3:<\/p>\n

    – \u0110\u1ec3 l\u00e0m 1 qu\u1ea3 c\u00e2n 200g ta c\u1ea7n \u0111o tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t l\u00e0m ra n\u00f3 v\u00e0 c\u00f3 1 s\u1ee3i chi bu\u1ed9c v\u00e0o qu\u1ea3 c\u00e2n.<\/p>\n

    – 1 b\u00ecnh chia \u0111\u1ed9 c\u00f3 GH\u0110 250 cm^{3<\/sup>, mi\u1ec7ng r\u1ed9ng \u0111\u1ebf c\u1ee7a n\u00f3 c\u00f3 th\u1ec3 cho l\u1ecdt q\u1ee7a c\u00e2n v\u00e0o trong b\u00ecnh. B\u00ecnh n\u00e0y c\u00f3 ch\u1ee9a kho\u00e1ng 100 cm3<\/sup> n\u01b0\u1edbc.<\/p>\n}

    – 1 l\u1ef1c k\u1ebf c\u00f3 GH\u0110 \u00edt nh\u1ea5t l\u00e0 2,5N.<\/p>\n

    Gi\u1ea3i:<\/strong><\/p>\n

    Ta th\u1ea3 ch\u00ecm qu\u1ea3 c\u00e2n n\u00e0y v\u00e0o b\u00ecnh chia \u0111\u1ed9.<\/p>\n

    Gi\u1ea3 s\u1eed ta th\u1ea5y m\u1ef1c n\u01b0\u1edbc d\u00e2ng l\u00ean \u0111\u1ebfn 120 m^{3<\/sup>.<\/p>\n}

    V\u1eady th\u00ec th\u1ec3 t\u00edch c\u1ee7a qu\u1ea3 c\u00e2n 200g l\u00e0: V = 120 – 100 = 20 (m^{3<\/sup>) = 0,00002(m3<\/sup>).<\/p>\n}

    Ta treo qu\u1ea3 c\u00e2n n\u00e0y v\u00e0o l\u1ef1c k\u1ebf \u0111\u1ec3 x\u00e1c \u0111\u1ecbnh tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a qu\u1ea3 c\u00e2n: 2 N (do p = 10m = 10 . 0,2 = 2N).<\/p>\n

    V\u1eady ta c\u00f3 tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t l\u00e0m ra qu\u1ea3 c\u00e2n (200g) l\u00e0:<\/p>\n

    d = P \/ V = 2 \/ 0,00002 = 100000 (N\/m^{3<\/sup>).<\/p>\n}

    B\u00e0i t\u1eadp 4:<\/strong> H\u00e3y t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a 1 chi\u1ebfc d\u1ea7m s\u1eaft m\u00e0 c\u00f3 th\u1ebf t\u00edch l\u00e0 40 dm^{3<\/sup>.<\/p>\n}

    Gi\u1ea3i:<\/strong><\/p>\n

    Theo b\u1ea3ng kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang ta th\u1ea5y s\u1eaft c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang; D = 7800kg\/m^{3<\/sup><\/p>\n}

    Th\u1ec3 t\u00edch c\u1ee7a d\u1ea7m s\u1eaft l\u00e0 V = 40dm^{3<\/sup> = 0,04 m3<\/sup><\/p>\n}

    V\u1eady kh\u1ed1i l\u01b0\u1ee3ng d\u1ea7m s\u1eaft l\u00e0:<\/p>\n

    m = D.V = 7800.0,04 = 312 (kg)<\/p>\n

    2\/ B\u00e0i t\u1eadp \u00e1p d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh m3 t\u1ef1 gi\u1ea3i<\/h3>\n

    Sau \u0111\u00e2y l\u00e0 m\u1ed9t s\u1ed1 b\u00e0i t\u1eadp tamcaotrithuc.com \u0111\u01b0a ra \u0111\u1ec3 c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u1ef1 v\u1eadn d\u1ee5ng c\u00f4ng th\u1ee9c t\u00ednh m3 v\u00e0o vi\u1ec7c gi\u1ea3i b\u00e0i t\u1eadp<\/p>\n

    B\u00e0i t\u1eadp 1:<\/strong> C\u00f3 2 chai thu\u1ef7 tinh gi\u1ed1ng h\u1ec7t nhau, 1 chai ch\u1ee9a \u0111\u1ea7y n\u01b0\u1edbc v\u00e0 1 chai ch\u1ee9a \u0111\u1ea7y d\u1ea7u. Khi ta th\u1ea3 2 chai th\u1ee7y tinh n\u00e0y v\u00e0o trong ch\u1eadu n\u01b0\u1edbc th\u00ec 1 chai ch\u00ecm xu\u1ed1ng \u0111\u00e1y c\u00f2n 1 chai th\u00ec l\u01a1 l\u1eedng trong n\u01b0\u1edbc. N\u1ebfu ta th\u1ea3 chai ch\u1ee9a \u0111\u1ea7y n\u01b0\u1edbc v\u00e0o trong 1 ch\u1eadu ch\u1ee9a \u0111\u1ea7y n\u01b0\u1edbc th\u00ec th\u1ec3 t\u00edch n\u01b0\u1edbc tr\u00e0n ra ngo\u00e0i l\u00e0 1 l\u00edt.<\/p>\n

    Bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a thu\u1ef7 tinh l\u00e0m v\u1ecf chai l\u00e0 2,4g\/cm^{3<\/sup> v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a d\u1ea7u l\u00e0 0,8g\/cm3<\/sup> v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a n\u01b0\u1edbc l\u00e0 1 g\/cm3<\/sup>. H\u00e3y x\u00e1c \u0111\u1ecbnh dung t\u00edch c\u1ee7a chai th\u1ee7y tinh.<\/p>\n}

    <\/p>\n

    B\u00e0i t\u1eadp 2:<\/strong> Cho 1 qu\u1ea3 n\u1eb7ng c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 0,27kg, c\u00f3 th\u1ec3 t\u00edch l\u00e0 0,0001 m^{3<\/sup>.<\/p>\n}

    \n
    1. H\u00e3y t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t \u0111\u00e3 l\u00e0m ra v\u1eadt? H\u00e3y cho bi\u1ebft v\u1eadt \u0111\u01b0\u1ee3c l\u00e0m b\u1eb1ng ch\u1ea5t g\u00ec?<\/li>\n
    2. H\u00e3y t\u00ednh tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a v\u1eadt?<\/li>\n
    3. N\u1ebfu ta treo qu\u1ea3 n\u1eb7ng n\u00e0y v\u00e0o 1 l\u1ef1c k\u1ebf th\u00ec l\u1ef1c k\u1ebf s\u1ebd ch\u1ec9 gi\u00e1 tr\u1ecb l\u00e0 bao nhi\u00eau?<\/li>\n<\/ol>\n

       ( Bi\u1ebft D_{\u00a0<\/sub>s\u1eaft <\/sub>\u00a0= 7800kg\/m^{3<\/sup>, D\u00a0<\/sub>\u0111\u00e1 <\/sub>\u00a0= 2600kg\/m3<\/sup> v\u00e0 Dnh\u00f4m \u00a0<\/sub>= 2700kg\/m3<\/sup>)<\/p>\n}}

       \u00a0B\u00e0i t\u1eadp 3:\u00a0<\/strong>C\u00f3 1 b\u00ecnh chia \u0111\u1ed9 c\u00f3 ch\u1ee9a n\u01b0\u1edbc \u1edf v\u1ea1ch l\u00e0 32 cm^{3<\/sup>. Ta th\u1ea3 2 h\u00f2n bi gi\u1ed1ng h\u1ec7t nhau v\u00e0o trong b\u00ecnh th\u00ec m\u1ee9c n\u01b0\u1edbc d\u00e2ng l\u00ean \u1edf v\u1ea1ch l\u00e0 42 cm3<\/sup>. H\u00e3y t\u00ednh:<\/p>\n}

       a\/ Th\u1ec3 t\u00edch c\u1ee7a 1 vi\u00ean bi?<\/p>\n

       b\/ Kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t \u0111\u00e3 l\u00e0m ra vi\u00ean bi theo \u0111\u01a1n v\u1ecb l\u00e0 kg\/m^{3<\/sup>? Cho bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t vi\u00ean bi l\u00e0 39 gam.<\/p>\n}

       c\/ Tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a ch\u1ea5t \u0111\u00e3 l\u00e0m ra vi\u00ean bi n\u00e0y?<\/p>\n

       B\u00e0i t\u1eadp 4:<\/strong> Cho 1 kh\u1ed1i g\u1ed7 c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 2,4 kg v\u00e0 c\u00f3 th\u1ec3 t\u00edch l\u00e0 3 dm^{3<\/sup>.<\/p>\n}

       a\/ H\u00e3y t\u00ednh tr\u1ecdng l\u01b0\u1ee3ng c\u1ee7a kh\u1ed1i g\u1ed7 n\u00e0y.<\/p>\n

       b\/ H\u00e3y t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang c\u1ee7a kh\u1ed1i g\u1ed7.<\/p>\n

       c\/ H\u00e3y t\u00ednh tr\u1ecdng l\u01b0\u1ee3ng ri\u00eang c\u1ee7a kh\u1ed1i g\u1ed7.<\/p>\n

       d\/ Ng\u01b0\u1eddi ta kho\u00e9t b\u1ecf \u1edf tr\u00ean kh\u1ed1i g\u1ed7 1 l\u1ed7 tr\u00f2n c\u00f3 th\u1ec3 t\u00edch l\u00e0 50 cm^{3<\/sup>. H\u00e3y t\u00ednh kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a ph\u1ea7n g\u1ed7 b\u1ecb kho\u00e9t b\u1ecf n\u00e0y.<\/p>\n}

       <\/p>\n

       B\u00e0i t\u1eadp 5:<\/strong> Cho 1 m\u1eabu h\u1ee3p kim g\u1ed3m ch\u00ec-th\u00e9p c\u00f3 kh\u1ed1i l\u01b0\u1ee3ng l\u00e0 \u00a0m = 664g v\u00e0 kh\u1ed1i l\u01b0\u1ee3ng ri\u00eang l\u00e0 D = 8,3 g\/cm^{3<\/sup>. H\u00e3y cho bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a th\u00e9p v\u00e0 ch\u00ec c\u00f3 trong h\u1ee3p kim n\u00e0y bi\u1ebft: D_{th\u00e9p<\/sub> = 7300 kg\/m3<\/sup> v\u00e0 Dch\u00ec<\/sub> = 11300 kg\/cm3<\/sup>.<\/p>\n","protected":false},"excerpt":{"rendered":"}}

       Trong th\u1ef1c t\u1ebf ta g\u1eb7p r\u1ea5t nhi\u1ec1u b\u00e0i to\u00e1n v\u1ec1 t\u00ednh m3 v\u00ec v\u1eady h\u00f4m nay tamcaotrithuc.com s\u1ebd c\u00f9ng c\u00e1c b\u1ea1n \u00f4n l\u1ea1i c\u00e1c c\u00f4ng th\u1ee9c t\u00ednh m3 v\u00e0 m\u1ed9t… <\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[414,418,407],"tags":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/8289"}],"collection":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/comments?post=8289"}],"version-history":[{"count":0,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/8289\/revisions"}],"wp:attachment":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media?parent=8289"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/categories?post=8289"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/tags?post=8289"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}