C\u00e2u 1. Trong s\u1ed1 c\u00e1c nh\u00e2n t\u1ed1 ti\u1ebfn h\u00f3a, nh\u00e2n t\u1ed1 kh\u00f4ng l\u00e0m thay \u0111\u1ed5i t\u1ea7n s\u1ed1 alen c\u1ee7a qu\u1ea7n th\u1ec3 nh\u01b0ng l\u00e0m thay \u0111\u1ed5i th\u00e0nh ph\u1ea7n ki\u1ec3u gen c\u1ee7a qu\u1ea7n th\u1ec3 theo h\u01b0\u1edbng t\u0103ng t\u1ea7n s\u1ed1 ki\u1ec3u gen \u0111\u1ed3ng h\u1ee3p, gi\u1ea3m t\u1ea7n s\u1ed1 ki\u1ec3u gen d\u1ecb h\u1ee3p:
\nA. Ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0B. Di nh\u1eadp gen
\nC. C\u00e1c y\u1ebfu t\u1ed1 ng\u1eabu nhi\u00ean \u00a0 \u00a0 \u00a0 D. Giao ph\u1ed1i kh\u00f4ng ng\u1eabu nhi\u00ean
\nC\u00e2u 2. Cho c\u00e1c bi\u1ec7n ph\u00e1p sau:
\n(1) \u0110\u01b0a th\u00eam gen l\u1ea1 v\u00e0o h\u1ec7 gen
\n(2) Thay \u0111\u1ed5i m\u00f4i tr\u01b0\u1eddng s\u1ed1ng c\u1ee7a sinh v\u1eadt \u0111\u1ec3 gen n\u00e0o \u0111\u00f3 c\u00f3 \u0111i\u1ec1u ki\u1ec7n bi\u1ec3u hi\u1ec7n ra ki\u1ec3u h\u00ecnh
\n(3) Lo\u1ea1i b\u1ecf m\u1ed9t gen s\u1eb5n c\u00f3 trong h\u1ec7 gen
\n(4) L\u00e0m bi\u1ebfn \u0111\u1ed5i m\u1ed9t gen s\u1eb5n c\u00f3 trong h\u1ec7 gen \u0111\u1ec3 n\u00f3 t\u1ea1o ra nhi\u1ec1u s\u1ea3n ph\u1ea9m h\u01a1n
\n(5) L\u00e0m b\u1ea5t ho\u1ea1t m\u1ed9t gen n\u00e0o \u0111\u00f3
\n(6) G\u00e2y \u0111\u1ed9t bi\u1ebfn gen thay th\u1ebf nh\u01b0ng v\u1eabn c\u00f9ng m\u00e3 h\u00f3a cho m\u1ed9t lo\u1ea1i axit amin
\nC\u00f3 bao nhi\u00eau bi\u1ec7n ph\u00e1p kh\u00f4ng d\u00f9ng \u0111\u1ec3 t\u1ea1o ra sinh v\u1eadt bi\u1ebfn \u0111\u1ed5i gen?
\nA. 3 \u00a0 \u00a0 \u00a0 B. 2 \u00a0 \u00a0 \u00a0C. 4 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0D. 5
\nC\u00e2u 3. Quy tr\u00ecnh t\u1ea1o ra nh\u1eefng t\u1ebf b\u00e0o ho\u1eb7c sinh v\u1eadt c\u00f3 gen b\u1ecb bi\u1ebfn \u0111\u1ed5i, c\u00f3 th\u00eam gen m\u1edbi, t\u1eeb \u0111\u00f3 t\u1ea1o ra c\u00e1c c\u01a1 th\u1ec3 v\u1edbi nh\u1eefng \u0111\u1eb7c \u0111i\u1ec3m m\u1edbi \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0:
\nA. c\u00f4ng ngh\u1ec7 vi sinh v\u1eadt. \u00a0 \u00a0B. c\u00f4ng ngh\u1ec7 gen. \u00a0 \u00a0 C. c\u00f4ng ngh\u1ec7 t\u1ebf b\u00e0o. \u00a0 \u00a0 D. c\u00f4ng ngh\u1ec7 sinh h\u1ecdc.
\nC\u00e2u 4. Th\u1ef1c ch\u1ea5t c\u1ee7a s\u1ef1 ph\u00e2n ly \u0111\u1ed9c l\u1eadp l\u00e0:
\nA. S\u1ef1 ph\u00e2n ly \u0111\u1ed9c l\u1eadp c\u1ee7a c\u00e1c alen trong qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n
\nB. S\u1ef1 ph\u00e2n ly ki\u1ec3u h\u00ecnh theo t\u1ec9 l\u1ec7 9:3:3:1
\nC. S\u1ef1 ph\u00e2n ly \u0111\u1ed9c l\u1eadp c\u1ee7a c\u00e1c t\u00ednh tr\u1ea1ng
\nD. S\u1ef1 t\u1ed5 h\u1ee3p c\u1ee7a c\u00e1c alen trong qu\u00e1 tr\u00ecnh th\u1ee5 tinh
\nC\u00e2u 5. Khi n\u00f3i v\u1ec1 \u0111\u1ed9t bi\u1ebfn nhi\u1ec5m s\u1eafc th\u1ec3, ph\u00e1t bi\u1ec3u n\u00e0o sau \u0111\u00e2y kh\u00f4ng ch\u00ednh x\u00e1c?
\nA. Trao \u0111\u1ed5i ch\u00e9o kh\u00f4ng c\u00e2n gi\u1eefa hai trong 4 cromatit trong c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 t\u01b0\u01a1ng \u0111\u1ed3ng d\u1eabn \u0111\u1ebfn \u0111\u1ed9t bi\u1ebfn l\u1eb7p \u0111o\u1ea1n
\nB. Ng\u01b0\u1eddi ta c\u00f3 th\u1ec3 g\u00e2y \u0111\u1ed9t bi\u1ebfn m\u1ea5t \u0111o\u1ea1n nh\u1ecf \u0111\u1ec3 lo\u1ea1i b\u1ecf c\u00e1c gen kh\u00f4ng mong mu\u1ed1n
\nC. \u0110\u1ed9t bi\u1ebfn \u0111\u1ea3o \u0111o\u1ea1n c\u00f3 th\u1ec3 gi\u00fap h\u00ecnh th\u00e0nh lo\u00e0i m\u1edbi
\nD. \u0110\u1ed9t bi\u1ebfn l\u1eb7p \u0111o\u1ea1n d\u00f9ng \u0111\u1ec3 x\u00e2y d\u1ef1ng b\u1ea3n \u0111\u1ed3 gen
\nC\u00e2u 6. M\u1ed9t qu\u1ea7n th\u1ec3 c\u00f3 c\u1ea5u tr\u00fac di truy\u1ec1n 0,4Aa: 0,6aa. N\u1ebfu bi\u1ebft alen A l\u00e0 tr\u1ed9i kh\u00f4ng ho\u00e0n to\u00e0n so v\u1edbi alen a th\u00ec t\u1ec9 l\u1ec7 c\u00e1 th\u1ec3 mang ki\u1ec3u h\u00ecnh tr\u1ed9i c\u1ee7a qu\u1ea7n th\u1ec3 n\u00f3i tr\u00ean khi \u0111\u1ea1t tr\u1ea1ng th\u00e1i c\u00e2n b\u1eb1ng l\u00e0:
\nA. 16% \u00a0 \u00a0 B. 4% \u00a0 \u00a0 \u00a0C. 36% \u00a0 \u00a0 D. 40%
\nC\u00e2u 7. Theo quan ni\u1ec7m ti\u1ebfn h\u00f3a hi\u1ec7n \u0111\u1ecba, \u0111\u01a1n v\u1ecb ti\u1ebfn h\u00f3a c\u01a1 s\u1edf l\u00e0:
\nA. Qu\u1ea7n th\u1ec3 B. C\u00e1 th\u1ec3 C. Qu\u1ea7n x\u00e3 D. Lo\u00e0i
\nC\u00e2u 8. C\u00e2y pomato \u2013 c\u00e2y lai gi\u1eefa khoai t\u00e2y v\u00e0 c\u00e0 chua \u0111\u01b0\u1ee3c t\u1ea1o ra b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p
\nA. c\u1ea5y truy\u1ec1n ph\u00f4i. B. dung h\u1ee3p t\u1ebf b\u00e0o tr\u1ea7n.
\nC. nu\u00f4i c\u1ea5y t\u1ebf b\u00e0o th\u1ef1c v\u1eadt invitro t\u1ea1o m\u00f4 s\u1eb9o. D. nu\u00f4i c\u1ea5y h\u1ea1t ph\u1ea5n.
\nC\u00e2u 9. D\u01b0\u1edbi \u0111\u00e2y l\u00e0 c\u00e1c b\u01b0\u1edbc trong c\u00e1c quy tr\u00ecnh t\u1ea1o gi\u1ed1ng m\u1edbi:
\nI. Cho t\u1ef1 th\u1ee5 ph\u1ea5n ho\u1eb7c lai xa \u0111\u1ec3 t\u1ea1o ra c\u00e1c gi\u1ed1ng thu\u1ea7n ch\u1ee7ng.
\nII. Ch\u1ecdn l\u1ecdc c\u00e1c th\u1ec3 \u0111\u1ed9t bi\u1ebfn c\u00f3 ki\u1ec3u h\u00ecnh mong mu\u1ed1n.
\nIII. X\u1eed l\u00fd m\u1eabu v\u1eadt b\u1eb1ng t\u00e1c nh\u00e2n \u0111\u1ed9t bi\u1ebfn.
\nIV. T\u1ea1o d\u00f2ng thu\u1ea7n ch\u1ee7ng.
\nQuy tr\u00ecnh n\u00e0o sau \u0111\u00e2y \u0111\u00fang nh\u1ea5t trong vi\u1ec7c t\u1ea1o gi\u1ed1ng b\u1eb1ng ph\u01b0\u01a1ng ph\u00e1p g\u00e2y \u0111\u1ed9t bi\u1ebfn?
\nA. I \u2192 III \u2192 II. B. III \u2192 II \u2192 IV. C. II \u2192 III \u2192 IV D. III \u2192 II \u2192 I.
\nC\u00e2u 10. Nh\u1eefng ph\u00e9p lai n\u00e0o sau \u0111\u00e2y g\u1eafn li\u1ec1n v\u1edbi qu\u00e1 tr\u00ecnh \u0111a b\u1ed9i h\u00f3a?
\n(1) 4n x 4n =4n
\n(2) 4n x 2n = 3n
\n(3) 2n x 2n = 4n
\n(4) 3n x 3n = 6n
\nA. 2, 4 \u00a0B. 3,4 \u00a0 \u00a0 C. 1, 3 \u00a0D. 1,2
\nC\u00e2u 11. C\u01a1 th\u1ec3 c\u00f3 ki\u1ec3u gen AaBB, trong qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n 1 x\u1ea3y ra r\u1ed1i lo\u1ea1n kh\u00f4ng ph\u00e2n ly \u1edf c\u1eb7p Aa; Gi\u1ea3m ph\u00e2n 2 di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng. C\u00e1c giao t\u1eed c\u00f3 th\u1ec3 \u0111\u01b0\u1ee3c t\u1ea1o ra l\u00e0:
\nA. AaBB; AB; aB; O B. AABB; aaBB; AB; aB C. A, a, B, Aa, BB D. AB; aB; AaB; B
\nC\u00e2u 12. M\u1ed9t qu\u1ea7n th\u1ec3 c\u00f3 TPKG: 0,6AA + 0,4Aa = 1. T\u1ec9 l\u1ec7 c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen aa c\u1ee7a qu\u1ea7n th\u1ec3 \u1edf th\u1ebf h\u1ec7 sau khi t\u1ef1 ph\u1ed1i l\u00e0
\nA. 0,25AA: 0,5Aa: 0,25aa B. 0,6AA: 0,4Aa C. 0,64AA: 0,32Aa: 0,04aa D. 0,7AA: 0,2Aa: 0,1aa
\nC\u00e2u 13. B\u1ec7nh\/ h\u1ed9i ch\u1ee9ng di truy\u1ec1n do \u0111\u1ed9t bi\u1ebfn c\u1ea5u tr\u00fac NST g\u00e2y ra l\u00e0:
\nA. T\u1eadt d\u00ednh ng\u00f3n tay th\u1ee9 2 v\u00e0 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 B. Ung th\u01b0 m\u00e1u
\nC. M\u00e1u kh\u00f3 \u0111\u00f4ng \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 D. M\u00f9 m\u00e0u
\nC\u00e2u 14. Khi n\u00f3i v\u1ec1 qu\u1ea7n th\u1ec3 t\u1ef1 ph\u1ed1i, n\u1ed9i dung n\u00e0o sau \u0111\u00e2y kh\u00f4ng ch\u00ednh x\u00e1c?
\nA. Qu\u1ea7n th\u1ec3 t\u1ef1 ph\u1ed1i \u0111a h\u00ecnh v\u1ec1 ki\u1ec3u gen v\u00e0 ki\u1ec3u h\u00ecnh h\u01a1n qu\u1ea7n th\u1ec3 giao ph\u1ed1i
\nB. T\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i ki\u1ec3u gen d\u1ecb h\u1ee3p ng\u00e0y c\u00e0ng gi\u1ea3m qua c\u00e1c th\u1ebf h\u1ec7 t\u1ef1 ph\u1ed1i
\nC. Trong t\u1ef1 nhi\u00ean v\u1eabn t\u1ed3n t\u1ea1i c\u00e1c qu\u1ea7n th\u1ec3 t\u1ef1 ph\u1ed1i ho\u1eb7c giao ph\u1ed1i c\u1eadn huy\u1ebft
\nD. Qu\u00e1 tr\u00ecnh t\u1ef1 ph\u1ed1i l\u00e0m cho qu\u1ea7n th\u1ec3 d\u1ea7n ph\u00e2n h\u00f3a th\u00e0nh c\u00e1c d\u00f2ng thu\u1ea7n
\nC\u00e2u 15. Trong qu\u00e1 tr\u00ecnh sinh s\u1ea3n h\u1eefu t\u00ednh, c\u1ea5u tr\u00fac n\u00e0o \u0111\u01b0\u1ee3c truy\u1ec1n \u0111\u1ea1t nguy\u00ean v\u1eb9n t\u1eeb \u0111\u1eddi b\u1ed1 m\u1eb9 sang con c\u00e1i?
\nA. Nhi\u1ec5m s\u1eafc th\u1ec3 B. T\u00ednh tr\u1ea1ng C. Alen D. Nh\u00e2n t\u1ebf b\u00e0o
\nC\u00e2u 16. C\u00e1c c\u01a1 quan n\u00e0o sau \u0111\u00e2y l\u00e0 c\u00e1c c\u01a1 quan t\u01b0\u01a1ng t\u1ef1?
\nA. Chi tr\u01b0\u1edbc c\u1ee7a ng\u1ef1a v\u00e0 chi tr\u01b0\u1edbc c\u1ee7a ng\u01b0\u1eddi B. C\u00e1nh b\u01b0\u1edbm v\u00e0 c\u00e1nh d\u01a1i
\nC. Tai m\u00e8o v\u00e0 tai d\u01a1i D. C\u00e1nh chin v\u00e0 c\u00e1nh d\u01a1i
\nC\u00e2u 17. M\u1ed9t c\u01a1 th\u1ec3 c\u00f3 ki\u1ec3u gen AaBbDD. Qu\u00e1 tr\u00ecnh gi\u1ea3m ph\u00e2n c\u00f3 12% s\u1ed1 t\u1ebf b\u00e0o b\u1ecb r\u1ed1i lo\u1ea1n ph\u00e2n ly c\u1ee7a c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 Bb \u1edf gi\u1ea3m ph\u00e2n 1; gi\u1ea3m ph\u00e2n 2 di\u1ec5n ra b\u00ecnh th\u01b0\u1eddng. Trong c\u00e1c giao t\u1eed \u0111\u01b0\u1ee3c sinh ra, l\u1ea5y ng\u1eabu nhi\u00ean 1 giao t\u1eed th\u00ec x\u00e1c su\u1ea5t \u0111\u1ec3 thu \u0111\u01b0\u1ee3c giao t\u1eed mang ki\u1ec3u gen AbbD l\u00e0 bao nhi\u00eau?
\nA. 12% B. 3% C. 1,5% D. 6%
\nC\u00e2u 18. Vect\u01a1 chuy\u1ec3n gen \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng ph\u1ed5 bi\u1ebfn l\u00e0
\nA. plasmit. B. th\u1ef1c khu\u1ea9n th\u1ec3 C. E. coli. D. vir\u00fat.
\nC\u00e2u 19. M\u1ed9t qu\u1ea7n th\u1ec3 c\u00f3 c\u1ea5u tr\u00fac di truy\u1ec1n 0,04 AA + 0,32 Aa + 0,64 aa = 1. T\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a alen A, a l\u1ea7n l\u01b0\u1ee3t l\u00e0:
\nA. 0,8 ; 0,2 B. 0,2 ; 0,8 C. 0,7 ; 0,3 D. 0,3 ; 0,7
\nC\u00e2u 20. Tr\u00ean ph\u00e2n t\u1eed mARN c\u1ee7a sinh v\u1eadt nh\u00e2n s\u01a1, b\u1ed9 ba 5\u2019AUG3\u2032 m\u00e3 h\u00f3a cho axit amin:
\nA. Foocmin methionin B. Phenyl alanin C. Lysin D. Methionin
\nC\u00e2u 21. \u1ede 1 lo\u00e0i th\u1ef1c v\u1eadt, khi cho giao ph\u1ea5n gi\u1eefa c\u00e2y hoa \u0111\u1ecf v\u00e0 c\u00e2y hoa tr\u1eafng \u0111\u1ec1u thu\u1ea7n ch\u1ee7ng \u0111\u01b0\u1ee3c \u0111\u1eddi con F1 c\u00f3 100% c\u00e2y \u0111\u1ecf. F1 t\u1ef1 th\u1ee5 ph\u1ea5n \u0111\u01b0\u1ee3c F2. Ph\u00e9p lai n\u00e0o sau \u0111\u00e2y kh\u00f4ng x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c ki\u1ec3u gen c\u1ee7a c\u00e1c c\u00e2y hoa \u0111\u1ecf \u1edf F2?
\nA. C\u00e1c c\u00e2y hoa \u0111\u1ecf F2 lai v\u1edbi c\u00e2y hoa tr\u1eafng B. C\u00e1c c\u00e2y hoa \u0111\u1ecf F2 t\u1ef1 th\u1ee5 ph\u1ea5n
\nC. C\u00e1c c\u00e2y hoa \u0111\u1ecf F2 lai v\u1edbi c\u00e1c c\u00e2y hoa \u0111\u1ecf \u1edf P D. C\u00e1c c\u00e2y hoa \u0111\u1ecf F2 lai v\u1edbi c\u00e1c c\u00e2y hoa \u0111\u1ecf F1
\nC\u00e2u 22. Restrictaza v\u00e0 ligaza tham gia v\u00e0o c\u00f4ng \u0111o\u1ea1n n\u00e0o sau \u0111\u00e2y c\u1ee7a quy tr\u00ecnh chuy\u1ec3n gen?
\nA. T\u1ea1o \u0111i\u1ec1u ki\u1ec7n cho gen \u0111\u01b0\u1ee3c gh\u00e9p bi\u1ec3u hi\u1ec7n.
\nB. Chuy\u1ec3n ADN t\u00e1i t\u1ed5 h\u1ee3p v\u00e0o t\u1ebf b\u00e0o nh\u1eadn.
\nC. C\u1eaft, n\u1ed1i ADN c\u1ee7a t\u1ebf b\u00e0o cho v\u00e0 plasmit \u1edf nh\u1eefng \u0111i\u1ec3m x\u00e1c \u0111\u1ecbnh t\u1ea1o n\u00ean ADN t\u00e1i t\u1ed5 h\u1ee3p.
\nD. T\u00e1ch ADN c\u1ee7a nhi\u1ec5m s\u1eafc th\u1ec3 t\u1ebf b\u00e0o cho v\u00e0 t\u00e1ch plasm\u00edt ra kh\u1ecfi t\u1ebf b\u00e0o vi khu\u1ea9n.
\nC\u00e2u 23. \u1ede \u0111\u1eadu H\u00e0 Lan, A- cao; a- th\u1ea5p; B- hoa \u0111\u1ecf; b- hoa tr\u1eafng. C\u00e1c c\u1eb7p gen n\u1eb1m tr\u00ean c\u00e1c c\u1eb7p nhi\u1ec5m s\u1eafc th\u1ec3 kh\u00e1c nhau. Bi\u1ebft kh\u00f4ng x\u1ea3y ra \u0111\u1ed9t bi\u1ebfn. Trong c\u00e1c ph\u00e9p lai sau, ph\u00e9p lai n\u00e0o cho \u0111\u1eddi con c\u00f3 t\u1ec9 l\u1ec7 th\u00e2n th\u1ea5p, hoa tr\u1eafng chi\u1ebfm 25% ?
\n(1) AaBb x Aabb
\n(2) Aabb x aaBb
\n(3) aaBb x aaBB
\n(4) AaBB x aaBb
\nA. 3 B. 4 C. 1 D. 2
\nC\u00e2u 24. Ph\u00e2n t\u1eed \u0111\u00f3ng vai tr\u00f2 truy\u1ec1n \u0111\u1ea1t th\u00f4ng tin di truy\u1ec1n l\u00e0:
\nA. Protein B. AND C. tARN D. mARN
\nC\u00e2u 25. Trong ph\u00e9p lai gi\u1eefa hai c\u00e1 th\u1ec3 c\u00f3 ki\u1ec3u gen AaBbDdEeHH x AabbDDeehh. T\u1ec9 l\u1ec7 \u0111\u1eddi con c\u00f3 ki\u1ec3u gen \u0111\u1ed3ng h\u1ee3p v\u1ec1 3 c\u1eb7p v\u00e0 d\u1ecb h\u1ee3p v\u1ec1 2 c\u1eb7p gen l\u00e0:
\nA. 5 \/32 B. 1\/4 C. 27\/ 64 D. 9\/ 16
\nC\u00e2u 26. \u1ede ph\u00e9p lai AabbDdEe x AaBbDdEe thu \u0111\u01b0\u1ee3c F1. L\u1ea5y ng\u1eabu nhi\u00ean 1 c\u00e1 th\u1ec3 F1. X\u00e1c su\u1ea5t \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e1 th\u1ec3 c\u00f3 4 alen tr\u1ed9i l\u00e0 bao nhi\u00eau?
\nA. 3\/ 64 B. 5\/ 32 C. 15 \/ 64 D. 5 \/16
\nC\u00e2u 27. Nh\u00e2n t\u1ed1 ch\u00ednh chi ph\u1ed1i qu\u00e1 tr\u00ecnh ph\u00e1t sinh lo\u00e0i ng\u01b0\u1eddi \u1edf giai \u0111o\u1ea1n ng\u01b0\u1eddi t\u1ed1i c\u1ed5( ng\u01b0\u1eddi v\u01b0\u1ee3n h\u00f3a th\u1ea1ch) l\u00e0:
\nA. S\u1ef1 h\u00ecnh th\u00e0nh m\u1ea7m m\u1ed1ng t\u00f4n gi\u00e1o, ngh\u1ec7 thu\u1eadt
\nB. S\u1ef1 thay \u0111\u1ed5i \u0111i\u1ec1u ki\u1ec7n \u0111\u1ecba ch\u1ea5t, kh\u00ed h\u1eadu \u1edf k\u00ec th\u1ee9 3 \u0111\u1ea1i T\u00e2n Sinh
\nC. C\u1ea3i ti\u1ebfn c\u00f4ng c\u1ee5 lao \u0111\u1ed9ng
\nD. Qu\u00e1 tr\u00ecnh \u0111\u1ed9t bi\u1ebfn, giao ph\u1ed1i, ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean
\nC\u00e2u 28. \u0110\u1eb7c \u0111i\u1ec3m n\u00e0o d\u01b0\u1edbi \u0111\u00e2y kh\u00f4ng ph\u1ea3i l\u00e0 \u0111\u1eb7c \u0111i\u1ec3m di truy\u1ec1n c\u1ee7a gen l\u1eb7n tr\u00ean X kh\u00f4ng\u00a0 c\u00f3 alen t\u01b0\u01a1ng \u1ee9ng tr\u00ean Y
\nA. K\u1ebft qu\u1ea3 lai thu\u1eadn kh\u00e1c lai ngh\u1ecbch
\nB. Ki\u1ec3u h\u00ecnh l\u1eb7n lu\u00f4n c\u00f3 xu h\u01b0\u1edbng bi\u1ec3u hi\u1ec7n \u1edf gi\u1edbi XX
\nC. C\u00f3 hi\u1ec7n t\u01b0\u1ee3ng di truy\u1ec1n ch\u00e9o t\u1eeb m\u1eb9 -> con trai
\nD. T\u1ec9 l\u1ec7 ph\u00e2n ly ki\u1ec3u h\u00ecnh kh\u00f4ng \u0111\u1ed3ng \u0111\u1ec1u \u1edf hai gi\u1edbi
\nC\u00e2u 29. Th\u00e0nh ph\u1ea7n kh\u00f4ng c\u00f3 trong c\u1ea5u tr\u00fac c\u1ee7a Operon Lac l\u00e0:
\nA. Gen \u0111i\u1ec1u h\u00f2a B. V\u00f9ng kh\u1edfi \u0111\u1ed9ng C. V\u00f9ng v\u1eadn h\u00e0nh D. Gen c\u1ea5u tr\u00fac
\nC\u00e2u 30. M\u1ed9t qu\u1ea7n th\u1ec3 th\u1ef1c v\u1eadt c\u00f3 t\u1ec9 l\u1ec7 c\u00e1c ki\u1ec3u gen AA:Aa:aa = 1:1,5:2,5. Tr\u1ea3 qua qu\u00e1 tr\u00ecnh t\u1ef1 th\u1ee5 ph\u1ea5n b\u1eaft bu\u1ed9c, trong qu\u1ea7n th\u1ec3 c\u00f3 6400 c\u00e2y, trong \u0111\u00f3 c\u00e2y hoa h\u1ed3ng l\u00e0 240 c\u00e2y. Bi\u1ebft t\u00ednh tr\u1ea1ng \u0111\u1ecf l\u00e0 tr\u1ed9i so v\u1edbi tr\u1eafng. S\u1ed1 c\u00e2y \u0111\u1ecf v\u00e0 tr\u1eafng l\u00e0:
\nA. 4040 \u0111\u1ecf & 2120 tr\u1eafng B. 3840 \u0111\u1ecf& 2240 tr\u1eafng
\nC. 2120 c\u00e2y \u0111\u1ecf v\u00e0 4040 c\u00e2y tr\u1eafng D. 2240 \u0111\u1ecf& 3840 tr\u1eafng
\nC\u00e2u 31. K\u1ef9 thu\u1eadt n\u00e0o d\u01b0\u1edbi \u0111\u00e2y l\u00e0 \u1ee9ng d\u1ee5ng c\u00f4ng ngh\u1ec7 t\u1ebf b\u00e0o trong t\u1ea1o gi\u1ed1ng m\u1edbi \u1edf th\u1ef1c v\u1eadt?
\nA. Nu\u00f4i c\u1ea5y h\u1ea1t ph\u1ea5n.
\nB. Ph\u1ed1i h\u1ee3p v\u1eadt li\u1ec7u di truy\u1ec1n c\u1ee7a nhi\u1ec1u lo\u00e0i trong m\u1ed9t ph\u00f4i.
\nC. Ph\u1ed1i h\u1ee3p hai ho\u1eb7c nhi\u1ec1u ph\u00f4i t\u1ea1o th\u00e0nh th\u1ec3 kh\u1ea3m.
\nD. T\u00e1i t\u1ed5 h\u1ee3p th\u00f4ng tin di truy\u1ec1n c\u1ee7a nh\u1eefng lo\u00e0i kh\u00e1c xa nhau trong thang ph\u00e2n lo\u1ea1i.
\nC\u00e2u 32. N\u1ed9i dung n\u00e0o sau \u0111\u00e2y kh\u00f4ng ch\u00ednh x\u00e1c khi n\u00f3i v\u1ec1 \u0111\u1ed9t bi\u1ebfn gen?
\nA. \u0110\u1ed9t bi\u1ebfn gen l\u00e0 nh\u1eefng bi\u1ebfn \u0111\u1ed5i nh\u1ecf trong c\u1ea5u tr\u00fac c\u1ee7a gen, li\u00ean quan \u0111\u1ebfn 1 c\u1eb7p nucleotit( \u0111\u1ed9t bi\u1ebfn \u0111i\u1ec3m) hay m\u1ed9t s\u1ed1 c\u1eb7p nucleotit.
\nB. Nguy\u00ean nh\u00e2n ph\u00e1t sinh \u0111\u1ed9t bi\u1ebfn gen l\u00e0 do s\u1ef1 b\u1eaft c\u1eb7p kh\u00f4ng \u0111\u00fang trong nh\u00e2n \u0111\u00f4i AND, do nh\u1eefng sai h\u1ecfng ng\u1eabu nhi\u00ean, do t\u00e1c \u0111\u1ed9ng c\u00e1c t\u00e1c nh\u00e2n l\u00ed, h\u00f3a, sinh h\u1ecdc
\nC. \u0110\u1ed9t bi\u1ebfn \u0111i\u1ec3m c\u00f3 3 d\u1ea1ng: \u0110\u1ed9t bi\u1ebfn m\u1ea5t 1 c\u1eb7p Nu; Thay th\u1ebf 1 c\u1eb7p Nu n\u00e0y b\u1eb1ng 1 c\u1eb7p Nu kh\u00e1c; Th\u00eam 1 c\u1eb7p Nu
\nD. \u0110\u1ed9t bi\u1ebfn gen x\u1ea3y ra ph\u1ed5 bi\u1ebfn h\u01a1n v\u00e0 c\u00f3 h\u1ea1i h\u01a1n \u0111\u1ed9t bi\u1ebfn nhi\u1ec5m s\u1eafc th\u1ec3
\nC\u00e2u 33. X\u00e9t m\u1ed9t qu\u1ea7n th\u1ec3 c\u00f3 2 alen (A, a). Qu\u1ea7n th\u1ec3 kh\u1edfi \u0111\u1ea7u c\u00f3 s\u1ed1 c\u00e1 th\u1ec3 t\u01b0\u01a1ng \u1ee9ng v\u1edbi t\u1eebng lo\u1ea1i ki\u1ec3u gen l\u00e0: 65AA: 26Aa: 169aa. T\u1ea7n s\u1ed1 t\u01b0\u01a1ng \u0111\u1ed1i c\u1ee7a m\u1ed7i alen trong qu\u1ea7n th\u1ec3 n\u00e0y l\u00e0:
\nA. A = 0,25 ; a = 0,75 B. A = 0,50 ; a = 0,50 C. A = 0,30 ; a = 0,70 D. A = 0,35 ; a = 0,65
\nC\u00e2u 34. Trong th\u00e0nh ph\u1ea7n c\u1ea5u tr\u00fac c\u1ee7a m\u1ed9t gen \u0111i\u1ec3n h\u00ecnh, g\u1ed3m c\u00e1c th\u00e0nh ph\u1ea7n:
\nA. V\u00f9ng kh\u1edfi \u0111\u1ed9ng, v\u00f9ng m\u00e3 h\u00f3a, v\u00f9ng c\u1ea5u tr\u00fac B. V\u00f9ng \u0111i\u1ec1u h\u00f2a, v\u00f9ng m\u00e3 h\u00f3a, v\u00f9ng k\u1ebft th\u00fac
\nC. V\u00f9ng \u0111i\u1ec1u h\u00f2a, v\u00f9ng v\u1eadn h\u1ea1nh, v\u00f9ng k\u1ebft th\u00fac D. V\u00f9ng kh\u1edfi \u0111\u1ed9ng, v\u00f9ng v\u1eadn h\u00e0nh, v\u00f9ng k\u1ebft th\u00fac
\nC\u00e2u 35. Trong qu\u00e1 tr\u00ecnh ph\u00e2n b\u00e0o, c\u01a1 ch\u1ebf t\u00e1c \u0111\u1ed9ng c\u1ee7a c\u00f4nsixin l\u00e0
\nA. l\u00e0m cho t\u1ebf b\u00e0o to h\u01a1n b\u00ecnh th\u01b0\u1eddng. B. c\u1ea3n tr\u1edf s\u1ef1 ph\u00e2n chia c\u1ee7a t\u1ebf b\u00e0o.
\nC. c\u1ea3n tr\u1edf s\u1ef1 h\u00ecnh th\u00e0nh thoi v\u00f4 s\u1eafc. D. l\u00e0m cho b\u1ed9 nhi\u1ec5m s\u1eafc th\u1ec3 t\u0103ng l\u00ean.
\nC\u00e2u 36. Trong qu\u00e1 tr\u00ecnh h\u00ecnh th\u00e0nh c\u00e1c \u0111\u1eb7c \u0111i\u1ec3m th\u00edch nghi, c\u00e1c nh\u00e2n t\u1ed1 n\u00e0o \u0111\u00f3ng vai tr\u00f2 ch\u1ee7 y\u1ebfu?
\nA. \u0110\u1ed9t bi\u1ebfn, giao ph\u1ed1i v\u00e0 c\u00e1c c\u01a1 ch\u1ebf c\u00e1ch li B. \u0110\u1ed9t bi\u1ebfn, ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean, di nh\u1eadp gen
\nC. \u0110\u1ed9t bi\u1ebfn, giao ph\u1ed1i, ch\u1ecdn l\u1ecdc t\u1ef1 nhi\u00ean D. \u0110\u1ed9t bi\u1ebfn, giao ph\u1ed1i, nh\u1eadp gen
\nC\u00e2u 37. M\u1ed9t c\u01a1 th\u1ec3 c\u00f3 ki\u1ec3u gen AaBBDd. Bi\u1ebft r\u1eb1ng kh\u00f4ng c\u00f3 \u0111\u1ed9t bi\u1ebfn x\u1ea3y ra. C\u00e1c giao t\u1eed \u0111\u01b0\u1ee3c t\u1ea1o ra t\u1eeb c\u01a1 th\u1ec3 tr\u00ean l\u00e0:
\nA. Aa; BB; Dd B. AaBD; Abd; aBD; aBd C. ABD; Abd; aBD; aBd D. AaBBDd
\nC\u00e2u 38. Trong c\u00f4ng t\u00e1c t\u1ea1o gi\u1ed1ng v\u1eadt nu\u00f4i, ph\u01b0\u01a1ng ph\u00e1p n\u00e0o \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng ph\u1ed5 bi\u1ebfn nh\u1ea5t?
\nA. Ph\u01b0\u01a1ng ph\u00e1p g\u00e2y \u0111\u1ed9t bi\u1ebfn B. C\u00f4ng ngh\u1ec7 gen C. Lai h\u1eefu t\u00ednh D. C\u00f4ng ngh\u1ec7 t\u1ebf b\u00e0o
\nC\u00e2u 39. C\u01a1 th\u1ec3 Aaaa khi gi\u1ea3m ph\u00e2n cho giao t\u1eed Aa chi\u1ebfm t\u1ec9 l\u1ec7:
\nA. 1\/ 2 B. 1\/ 4 C. 2\/ 6 D. 4\/ 6
\nC\u00e2u 40. M\u1ed9t \u0111\u1ed9t bi\u1ebfn l\u00e0m gen A bi\u1ebfn \u0111\u1ed5i th\u00e0nh gen a. Ban \u0111\u1ea7u, gen a r\u1ea5t hi\u1ebfm g\u1eb7p trong qu\u1ea7n th\u1ec3 nh\u01b0ng sau \u0111\u00f3 ch\u00fang tr\u1edf n\u00ean chi\u1ebfm \u01b0u th\u1ebf. \u0110i\u1ec1u gi\u1ea3i th\u00edch n\u00e0o sau \u0111\u00e2y l\u00e0 h\u1ee3p l\u00fd nh\u1ea5t?
\nA. C\u00e1c c\u00e1 th\u1ec3 mang gen \u0111\u1ed9t bi\u1ebfn giao ph\u1ed1i v\u1edbi nhau l\u00e0m ph\u00e1t t\u00e1n gen a trong qu\u1ea7n th\u1ec3
\nB. Do nhi\u1ec1u c\u00e1 th\u1ec3 trong qu\u1ea7n th\u1ec3 \u0111\u1ec1u b\u1ecb \u0111\u1ed9t bi\u1ebfn t\u1eeb gen A th\u00e0nh gen a
\nC. Do m\u00f4i tr\u01b0\u1eddng s\u1ed1ng thay \u0111\u1ed5i theo h\u01b0\u1edbng x\u00e1c \u0111\u1ecbnh v\u00e0 gen A c\u00f3 kh\u1ea3 n\u0103ng th\u00edch nghi cao h\u01a1n
\nD. Do c\u00e1 th\u1ec3 ban \u0111\u1ea7u ti\u1ebfp t\u1ee5c b\u1ecb \u0111\u1ed9t bi\u1ebfn l\u1eb7p \u0111o\u1ea1n l\u00e0m t\u0103ng alen a trong qu\u1ea7n th\u1ec3<\/p>\n","protected":false},"excerpt":{"rendered":"
40 c\u00e2u tr\u1eafc nghi\u1ec7m Sinh h\u1ecdc l\u1edbp 12 C\u00e2u 1. Trong s\u1ed1 c\u00e1c nh\u00e2n t\u1ed1 ti\u1ebfn h\u00f3a, nh\u00e2n t\u1ed1 kh\u00f4ng l\u00e0m thay \u0111\u1ed5i t\u1ea7n s\u1ed1 alen c\u1ee7a qu\u1ea7n th\u1ec3 nh\u01b0ng… <\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[450,472],"tags":[],"amp_enabled":true,"_links":{"self":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/9992"}],"collection":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/comments?post=9992"}],"version-history":[{"count":0,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/posts\/9992\/revisions"}],"wp:attachment":[{"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/media?parent=9992"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/categories?post=9992"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/onthitot.com\/wp-json\/wp\/v2\/tags?post=9992"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}